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ABR0033A - Максимум

x, y бодит тоонууд өгөгдөв. max(x, y)-г ол.

Input

x, y бутархай тоонуудыг зайгаар тусгаарлан нэг мөрөнд өгнө.

Output

max(x, y) тоог таслалаас хойш нэг оронгийн нарийвчлалтайгаар гаргана.

Example

Input:
3.14 1.4

Output:
3.1

Нэмсэн:sw40
Огноо:2007-10-19
Хугацааны хязгаарлалт:1s
Эх кодын хэмжээний хязгаарлалт:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Програмчлалын хэлүүд:Бүгд дараах хэлүүдээс бусад: ASM32-GCC MAWK BC C-CLANG NCSHARP CPP14 CPP14-CLANG COBOL COFFEE D-CLANG D-DMD DART ELIXIR ERL FANTOM FORTH GOSU GRV JS-RHINO JS-MONKEY JULIA KTLN NIM NODEJS OBJC OBJC-CLANG OCT PERL6 PICO PROLOG PYPY PYPY3 PY_NBC R RACKET RUST CHICKEN SQLITE SWIFT UNLAMBDA VB.NET
Эх сурвалж:Абрамов С. А.

hide comments
2020-09-21 15:37:29
import math
x , y = input().split()
x = float(x)
y = float(y)
if x > y :
print("{:.1f}".format(x))
else :
print("{:.1f}".format(y))
2018-03-16 09:31:57
hariult ni zurud bnaa aa
2013-01-16 06:23:41 shugarjaw
dw


2013-01-16 05:35:49 bataa
#include <stdio.h>
#include <conio.h>
#include <math.h>
int main(){
float a,p,s;
scanf("%f", &a);
p=(a+a+a)/2;
s=sqrt(p*(p-a)*(p-a)*(p-a));
printf("%.1f\n", s);
getch();
return 0;
}
2012-09-29 13:35:36 Tso .
hi guys
2011-10-05 13:46:14 hohohoho
#include <stdio.h>
#include <math.h>
#include <stdlib.h>
main (){
double x,y;
scanf("%lf%lf",&x,&y);
if(x>y) printf("%.1lf",x);
else printf("%.1lf",y);
return 0;
system ("pause");
}
2011-09-30 03:46:05 Monhkdalai
#include <stdio.h>
#include <math.h>
#include <stdlib.h>
main (){
double x,y;
scanf("%lf%lf",&x,&y);
if(x>y) printf("%.1lf",x);
else printf("%.1lf",y);
return 0;
system ("pause");
}


Last edit: 2011-09-30 04:24:53
2011-09-18 07:15:42 alaanka
tuslamj
2010-09-26 10:21:35 sw10d114
printf dr ne max(x,y)gevel bolno bizde duuddag funkts ne math.h mun uu
2010-09-10 12:21:34 sw10d019
borland dr hariu ni zuw garsan ch end C heldeer bodood ywuulsan chin hurwuulegiin aldaa gd bh ym....

Last edit: 2010-09-10 12:21:57
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