Problem hidden
|This problem was hidden by Editorial Board member probably because it has incorrect language|version or invalid test data, or description of the problem is not clear.|

ABR0068A - Палиндром

n натурал тоо өгөгдөв (n≤9999). n тоог дөрвөн цифртэй гэж үзээд палиндром (хөрвөдөг) эсэхийг нь шалга. Дөрвөн оронтой палиндром тооны жишээ: 2222, 6116, 0440.

Input

n натурал тоо өгөгдөнө

Output

Хэрэв уг тоо палиндром бол YES, үгүй бол NO гэсэн үг хэвлэнэ

Example

Input:
100

Output:
NO

Нэмсэн:sw40
Огноо:2007-10-29
Хугацааны хязгаарлалт:1s
Эх кодын хэмжээний хязгаарлалт:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Програмчлалын хэлүүд:Бүгд дараах хэлүүдээс бусад: ASM32-GCC MAWK BC C-CLANG NCSHARP CPP14 CPP14-CLANG COBOL COFFEE D-CLANG D-DMD DART ELIXIR ERL FANTOM FORTH GOSU GRV JS-RHINO JS-MONKEY JULIA KTLN NIM NODEJS OBJC OBJC-CLANG OCT PERL6 PICO PROLOG PYPY PYPY3 PY_NBC R RACKET RUST CHICKEN SQLITE SWIFT UNLAMBDA VB.NET
Эх сурвалж:Абрамов С. А.

hide comments
2020-09-23 04:01:18
import math
a=input()
a=int(a)
b=a//1000
c=a//100%10
d=a//10%10
e=a%10
if e==b and c==d :
print("YES")
else :
print("NO")
2019-10-03 09:19:59
#include <stdio.h>
int main()
{
int n,o1,o2,o3,o4;
scanf("%d",&n);
o4=n%10;
o1=n/1000;
o3=n/10%10;
o2=n/100%10;
if(o4==o1 && o3==o2)
{
printf("YES");
}
else
{
printf("NO");
}
return 0;
}
2017-10-31 19:25:20
#include<iostream>
using namespace std;
int main(){
int n,n1,n2;
cin >> n;
n1=n/1000;
n2=n%10;
if(n1==n2){
cout << "YES";
}
else{
cout << "NO";
}
return 0;
}
2012-03-15 08:05:00 uyangaa
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
main(){
int n,a,b,c,d;

scanf ("%d" , &n);
a=n/1000;
b=n/100%10;
c=n/10%10;
d=n%10;
if ((a==d) && (b==c)) printf ("YES");
else printf ("NO");
system ("pause");
return 0;
}


Last edit: 2012-03-15 08:05:23
2012-02-26 05:06:50 TukaTuka
BodoJ Chaddag ...
2012-01-05 09:46:24 AiR-Stark (DMTS) 10c
lol





























































































































































Last edit: 2012-01-05 09:59:57
2011-10-06 00:55:24 o.tsolmonbaatar
ygaad 7 huwisagch zarlaj bgaen?
toogoo?
2010-11-23 14:02:53 toogoo
#include<stdio.h>
main()
{
int n,k,s,x,y,z,p;

scanf("%d",&n);

k=n%10;
s=n/10;
p=s%10;
x=s/10;
y=x%10;
z=x/10;

if((k==z)&&(p==y)) printf("YES");
else printf("NO");
}
2010-11-07 22:06:35 Piotr KÄ…kol
Thank You! I got AC. :-)
2010-11-04 09:32:30 sw40
consider n as a 4-digit number
in: 440
out: yes (0440)
© Spoj.com. All Rights Reserved. Spoj uses Sphere Engine™ © by Sphere Research Labs.