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ABR0077A - Хоёрын зэрэг

n натурал тоо өгөгдөв. Дараах илэрхийллийн утгыг ол: 2^n

Input

n натурал тоо өгөгдөнө (n<64)

Output

2^n-ийн утгыг олж хэвлэнэ

Example

Input:
8

Output:
256

Нэмсэн:sw40
Огноо:2007-11-29
Хугацааны хязгаарлалт:1s
Эх кодын хэмжээний хязгаарлалт:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Програмчлалын хэлүүд:Бүгд дараах хэлүүдээс бусад: ASM32-GCC MAWK BC C-CLANG NCSHARP CPP14 CPP14-CLANG COBOL COFFEE D-CLANG D-DMD DART ELIXIR ERL FANTOM FORTH GOSU GRV JS-RHINO JS-MONKEY JULIA KTLN NIM NODEJS OBJC OBJC-CLANG OCT PERL6 PICO PROLOG PYPY PYPY3 PY_NBC R RACKET RUST CHICKEN SQLITE SWIFT UNLAMBDA VB.NET
Эх сурвалж:Абрамов С. А.

hide comments
2013-01-30 08:46:49 M.Enkhbileg
Уг бодлогыг C++ дээр бичвэл: 1 иймэрхүү
#include <iostream>
#include <stdlib.h>
using namespace std;
main()
{
int i, m=1;
cin >> i;
for(int j=0; j<i; j++)
{
m=2*m;
}
cout << m;
system("pause");
return 0;
}


Last edit: 2013-01-30 08:49:20
2012-10-17 12:16:01 Tso .
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
main(){
int n;
scanf("%d", &n);
int s=pow(2,n);
printf("%d", s);
system("pause");
return 0;
}
it's true ("_")
2012-10-13 10:35:37 Kris
#include <stdio.h>
#include <stdlib.h>
#include <cmath>
int main(){
int n, s;
scanf("%d", &n);
s = pow(2,n);
printf("%d", s);
system("pause");
return 0;
}
2012-04-30 07:59:38 Xuchitbaatar
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2012-04-30 07:21:54 Xuchitbaatar
bodlognuudaa bodoochee anduudantsaraa
2012-03-18 07:18:13 diedline
#include<stdio.h>
#include<stdlib.h>
main(){
int n;
scanf("%d",&n);
int p=1,i;
for(i=0;i<n;i++){
p*=2;
}
printf("%d",p);
return 0;
system("pause");
}
2012-03-01 09:50:50 ariunbayar_dmts



Last edit: 2012-03-15 03:29:31
2012-02-29 10:47:16 O&D
hutsaj ungaj h geer gazar sav
2012-02-29 10:39:51 AiR-Stark (DMTS) 10c


Last edit: 2012-02-29 10:45:28
2012-02-29 10:37:49 ariunbayar_dmts
ene chini chat bish shuu dahij buu yum bich ustga naadahaa
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