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ABR0086A - Оронгийн тоо

n натурал тоо өгөгдөв. n тоо хэдэн цифртэй вэ?

Input

n натурал тоо өгөгдөнө

Output

n тооны цифрүүдийн тоог хэвлэнэ (n<2000000000)

Example

Input:
1990

Output:
4

Нэмсэн:sw40
Огноо:2007-11-09
Хугацааны хязгаарлалт:1s
Эх кодын хэмжээний хязгаарлалт:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Програмчлалын хэлүүд:Бүгд дараах хэлүүдээс бусад: ASM32-GCC MAWK BC C-CLANG NCSHARP CPP14 CPP14-CLANG COBOL COFFEE D-CLANG D-DMD DART ELIXIR ERL FANTOM FORTH GOSU GRV JS-RHINO JS-MONKEY JULIA KTLN NIM NODEJS OBJC OBJC-CLANG OCT PERL6 PICO PROLOG PYPY PYPY3 PY_NBC R RACKET RUST CHICKEN SQLITE SWIFT UNLAMBDA VB.NET
Эх сурвалж:Абрамов С. А.

hide comments
2023-03-16 09:10:44
hii
2013-09-23 16:02:58 enkhbaysgalan
#include <stdio.h>
#include <stdlib.h>
main() {
int n, c=0;
scanf("%d", &n);
while(n>0){
c++;
n=n/10;
}
printf("%d", c);
system("pause");
return 0;
}

2013-01-30 08:31:43 M.Enkhbileg
C++ хэл дээр бичвэл
#include <iostream>
#include <stdlib.h>
using namespace std;
main()
{
int a, t, c=0, temp;
cin >> a;
while(1)
{
t=a/10;
temp = t;
a = temp;
c++;
if(t==0) break;
}
cout << c;
system("PAUSE");
return 0;
}

Last edit: 2013-02-04 06:23:08
2012-12-17 12:22:44 Bayartsetseg
kod ni dev c der ajillad bga hernee hurbuuleltin aldaa ged bhin yaj hurbulne ged bgn bol
2012-12-17 12:21:10 Bayartsetseg
#include<stdio.h>
#include<conio.h>
int main()
{
int n,t=0;
scanf("%d",&n);
while(n!=0){n/=10; t++;}
printf("%d",t);
getch();
}



Last edit: 2012-12-17 12:21:39
2012-10-26 12:27:00 Tso .
#include <stdio.h>
main(){
int n, c=0;
scanf("%d", &n);
while(n>0){
c++;
n=n/10;
}
printf("%d", c);
}

Last edit: 2012-11-24 03:28:53
2012-03-20 12:23:15 Nuudelchin
C++ hel dr bodoj chadah hun bn u?
\
2011-10-13 01:02:32 o.tsolmonbaatar
энэ бодлогын тайлбар нь хэрэгтэй байна
2011-01-02 04:19:37 dsn
#include<stdio.h>
#include<string.h>
#include<stdlib.h>
main() {
long p;
char a[2000000];
scanf("%s",&a);
printf("%ld",strlen(a));
system("pause") ;
}
2010-09-13 13:56:50 sw10d001
#include<stdio.h>
#include<string.h>


main()
{
long p;
char a[2000000];

scanf("%s",&a);

printf("%ld",strlen(a));
}


Last edit: 2010-09-13 13:57:58
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