ACPC10A  What’s Next
According to Wikipedia, an arithmetic progression (AP) is a sequence of numbers such that the difference of any two successive members of the sequence is a constant. For instance, the sequence 3, 5, 7, 9, 11, 13, . . . is an arithmetic progression with common difference 2. For this problem, we will limit ourselves to arithmetic progression whose common difference is a nonzero integer.
On the other hand, a geometric progression (GP) is a sequence of numbers where each term after the first is found by multiplying the previous one by a fixed nonzero number called the common ratio. For example, the sequence 2, 6, 18, 54, . . . is a geometric progression with common ratio 3. For this problem, we will limit ourselves to geometric progression whose common ratio is a nonzero integer.
Given three successive members of a sequence, you need to determine the type of the progression and the next successive member.
Input
Your program will be tested on one or more test cases. Each case is specified on a single line with three integers (−10, 000 < a1 , a2 , a3 < 10, 000) where a1 , a2 , and a3 are distinct.
The last case is followed by a line with three zeros.
Output
For each test case, you program must print a single line of the form:
XX v
where XX is either AP or GP depending if the given progression is an Arithmetic or Geometric Progression. v is the next member of the given sequence. All input cases are guaranteed to be either an arithmetic or geometric progressions.
Example
Input:
4 7 10
2 6 18
0 0 0
Output:
AP 13
GP 54
hide comments
y17prashant:
20171027 21:55:46
its easy but be careful to add a space in the output between Ap and the next no. it will


vkash:
20171016 11:04:26
AC in 4th go..!!


skeladoom07:
20170908 20:22:02
AC in one GO!!!


nuthanchandra:
20170906 19:54:04
There is no need to check for 5,0,5 or division by zero Last edit: 20170906 19:54:26 

phleg_matic:
20170829 19:40:33
Be careful about division by 0 and in the case of GP having one of the 2nd or 3rd number is zero 

Sebastian Ceronik:
20170823 10:02:35
While loop slapped me in the face :) wrong end condition costed me WA 

yuyao_1415926:
20170803 08:03:05
be careful for 5, 0, 5 

vishal3410:
20170714 18:35:19
it is not accepting could someone find mistakes http://ideone.com/ZNaxYd 

singlasahil221:
20170709 11:26:24
AC in one GO.


manish_nit97:
20170629 12:20:07
AC in 2nd GO!!

Added by:  Omar ElAzazy 
Date:  20101130 
Time limit:  1.799s 
Source limit:  50000B 
Memory limit:  1536MB 
Cluster:  Cube (Intel G860) 
Languages:  All except: ASM64 
Resource:  ACPC 2010 