ACPC10A - What’s Next

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According to Wikipedia, an arithmetic progression (AP) is a sequence of numbers such that the difference of any two successive members of the sequence is a constant. For instance, the sequence 3, 5, 7, 9, 11, 13 ... is an arithmetic progression with common difference 2. For this problem, we will limit ourselves to arithmetic progression whose common difference is a non-zero integer.

On the other hand, a geometric progression (GP) is a sequence of numbers where each term after the first is found by multiplying the previous one by a fixed non-zero number called the common ratio. For example, the sequence 2, 6, 18, 54 ... is a geometric progression with common ratio 3. For this problem, we will limit ourselves to geometric progression whose common ratio is a non-zero integer.

Given three successive members of a sequence, you need to determine the type of the progression and the next successive member.

Input

Your program will be tested on one or more test cases. Each case is specified on a single line with three integers (−10, 000 < a1, a2, a3 < 10, 000) where a1, a2, and a3 are distinct.

The last case is followed by a line with three zeros.

Output

For each test case, you program must print a single line of the form:
XX v
where XX is either AP or GP depending if the given progression is an Arithmetic or Geometric Progression. v is the next member of the given sequence. All input cases are guaranteed to be either an arithmetic or geometric progressions.

Example

Input:
4 7 10
2 6 18
0 0 0

Output:
AP 13
GP 54

hide comments
opcode: 2014-06-21 14:14:53

easy one

Shireen Nagdive: 2014-06-19 13:25:47

AC in first go :D

Surendra: 2014-06-15 09:00:50

@Abhishek the code is correct but just change positions of \n it should be used only after the %d in both AP and GP blocks. remove the \n before GP and place one after %d in AP. And bingo.

Abhishek Kumar: 2014-06-10 15:52:36

plz plz somebody check my solution..my sol is sworking correctly but spoj giving wrong ans..plz somebody help i m new at spoj...
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Last edit: 2022-08-10 15:40:40
rocode: 2014-06-06 08:53:07

AC in the first try . :D

Anubhav Mathur: 2014-06-01 21:05:19

GOT ac in 1st go , yippee :P

Satinjal Yadav: 2014-04-19 16:50:10

Easy one!!!

lokesh kumar: 2014-02-22 13:52:24

my program got accepted despite the fact that it prints AP 1 , for input 1 1 1. kindly check this error, because the definition says non zero common difference.

ivar.raknahs: 2014-02-19 17:24:33

got ac:)

square root of one..........: 2014-02-04 05:28:06

you just need to check by the formula of ap and gp even take input as int and ouput as int if u change that it will not be entertained


Added by:Omar ElAzazy
Date:2010-11-30
Time limit:1.799s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: ASM64
Resource:ACPC 2010