ADDREV  Adding Reversed Numbers
The Antique Comedians of Malidinesia prefer comedies to tragedies. Unfortunately, most of the ancient plays are tragedies. Therefore the dramatic advisor of ACM has decided to transfigure some tragedies into comedies. Obviously, this work is very hard because the basic sense of the play must be kept intact, although all the things change to their opposites. For example the numbers: if any number appears in the tragedy, it must be converted to its reversed form before being accepted into the comedy play.
Reversed number is a number written in arabic numerals but the order of digits is reversed. The first digit becomes last and vice versa. For example, if the main hero had 1245 strawberries in the tragedy, he has 5421 of them now. Note that all the leading zeros are omitted. That means if the number ends with a zero, the zero is lost by reversing (e.g. 1200 gives 21). Also note that the reversed number never has any trailing zeros.
ACM needs to calculate with reversed numbers. Your task is to add two reversed numbers and output their reversed sum. Of course, the result is not unique because any particular number is a reversed form of several numbers (e.g. 21 could be 12, 120 or 1200 before reversing). Thus we must assume that no zeros were lost by reversing (e.g. assume that the original number was 12).
Input
The input consists of N cases (equal to about 10000). The first line of the input contains only positive integer N. Then follow the cases. Each case consists of exactly one line with two positive integers separated by space. These are the reversed numbers you are to add.
Output
For each case, print exactly one line containing only one integer  the reversed sum of two reversed numbers. Omit any leading zeros in the output.
Example
Sample input: 3 24 1 4358 754 305 794 Sample output: 34 1998 1
hide comments
mib314:
20170425 10:48:34
got it Last edit: 20170425 10:51:35 

pankajnegi113:
20170423 20:38:49
AC in one go though i'm noobie :P 

akash619j:
20170416 09:52:26
@bks19 1


f2014044:
20170408 06:53:01
Python solution is quite easy. First timers can try it out. 

rcarv:
20170329 03:32:53
10 submissions before ac.


arthur1991:
20170328 18:45:51
i love qianqian 

bks19:
20170325 08:41:23
finally got AC in 20th try oh!!!!!!


ANKIT JAIN:
20170308 19:54:34
AC in one go :) 

tor_el:
20170223 13:43:19
AC in one go :) :) 

rohit9934:
20170210 08:23:56
AC in almost 50th Go. I was a newbie.I Still am.Dont lose hope 
Added by:  adrian 
Date:  20040606 
Time limit:  5s 
Source limit:  50000B 
Memory limit:  1536MB 
Cluster:  Cube (Intel G860) 
Languages:  All 
Resource:  ACM Central European Programming Contest, Prague 1998 