ADDREV  Adding Reversed Numbers
The Antique Comedians of Malidinesia prefer comedies to tragedies. Unfortunately, most of the ancient plays are tragedies. Therefore the dramatic advisor of ACM has decided to transfigure some tragedies into comedies. Obviously, this work is very hard because the basic sense of the play must be kept intact, although all the things change to their opposites. For example the numbers: if any number appears in the tragedy, it must be converted to its reversed form before being accepted into the comedy play.
Reversed number is a number written in arabic numerals but the order of digits is reversed. The first digit becomes last and vice versa. For example, if the main hero had 1245 strawberries in the tragedy, he has 5421 of them now. Note that all the leading zeros are omitted. That means if the number ends with a zero, the zero is lost by reversing (e.g. 1200 gives 21). Also note that the reversed number never has any trailing zeros.
ACM needs to calculate with reversed numbers. Your task is to add two reversed numbers and output their reversed sum. Of course, the result is not unique because any particular number is a reversed form of several numbers (e.g. 21 could be 12, 120 or 1200 before reversing). Thus we must assume that no zeros were lost by reversing (e.g. assume that the original number was 12).
Input
The input consists of N cases (equal to about 10000). The first line of the input contains only positive integer N. Then follow the cases. Each case consists of exactly one line with two positive integers separated by space. These are the reversed numbers you are to add.
Output
For each case, print exactly one line containing only one integer  the reversed sum of two reversed numbers. Omit any leading zeros in the output.
Example
Sample input: 3 24 1 4358 754 305 794 Sample output: 34 1998 1
hide comments
ronlek:
20170812 12:29:40
ac in one in 0.0. 

Radha Krishna:
20170809 00:31:07
ac one go in 0.0


shubhamivane:
20170706 21:22:07
Can anybody tell me what's the problem in my code, I am getting run time error I am using stack and queue template class from STL. This is the link to my source code http://ideone.com/q9u8fF . Last edit: 20170706 21:22:34 

suvro_coder:
20170702 20:30:15
ac in one go in 0.01 seconds 

codehead1997:
20170628 09:49:16
guyz i am getting warning "time limit exceeding" since my last two program.


coder_at_work:
20170625 17:25:00
@d_y1997 Answer of 3000+3000 is 6 and not 6000.


d_y1997:
20170612 22:04:30
question is badly described .. since acccording to question , 3000 + 3000 = 6000 , but on googling solution i found 6 .....and I was trying by vector , it shows me runtime error ...don't know why? please help me by commenting 

akshit_312:
20170612 13:53:56
Can we do it from array? Last edit: 20170612 13:55:10 

akhil_777:
20170601 13:53:22
Comments are pretty messed up. I was using two scanner objects to take test case and the inputs which was the real cause of not getting accepted.


kocharee:
20170529 13:21:30
ac in one go! :) Last edit: 20170529 14:28:59 
Added by:  adrian 
Date:  20040606 
Time limit:  5s 
Source limit:  50000B 
Memory limit:  1536MB 
Cluster:  Cube (Intel G860) 
Languages:  All 
Resource:  ACM Central European Programming Contest, Prague 1998 