ARITH  Simple Arithmetics
One part of the new WAP portal is also a calculator computing expressions with very long numbers. To make the output look better, the result is formated the same way as is it usually used with manual calculations.
Your task is to write the core part of this calculator. Given two numbers and the requested operation, you are to compute the result and print it in the form specified below. With addition and subtraction, the numbers are written below each other. Multiplication is a little bit more complex: first of all, we make a partial result for every digit of one of the numbers, and then sum the results together.
Input
There is a single positive integer T on the first line of input (equal to about 1000). It stands for the number of expressions to follow. Each expression consists of a single line containing a positive integer number, an operator (one of +,  and *) and the second positive integer number. Every number has at most 500 digits. There are no spaces on the line. If the operation is subtraction, the second number is always lower than the first one. No number will begin with zero.
Output
For each expression, print two lines with two given numbers, the second number below the first one, last digits (representing unities) must be aligned in the same column. Put the operator right in front of the first digit of the second number. After the second number, there must be a horizontal line made of dashes ().
For each addition or subtraction, put the result right below the horizontal line, with last digit aligned to the last digit of both operands.
For each multiplication, multiply the first number by each digit of the second number. Put the partial results one below the other, starting with the product of the last digit of the second number. Each partial result should be aligned with the corresponding digit. That means the last digit of the partial product must be in the same column as the digit of the second number. No product may begin with any additional zeros. If a particular digit is zero, the product has exactly one digit  zero. If the second number has more than one digit, print another horizontal line under the partial results, and then print the sum of them.
There must be minimal number of spaces on the beginning of lines, with respect to other constraints. The horizontal line is always as long as necessary to reach the left and right end of both numbers (and operators) directly below and above it. That means it begins in the same column where the leftmost digit or operator of that two lines (one below and one above) is. It ends in the column where is the rightmost digit of that two numbers. The line can be neither longer nor shorter than specified.
Print one blank line after each test case, including the last one.
Example
Sample Input:
4 12345+67890 324111 325*4405 1234*4
Sample Output:
12345 +67890  80235 324 111  213 325 *4405  1625 0 1300 1300  1431625 1234 *4  4936Warning: large Input/Output data, be careful with certain languages.
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tarptaeya:
20180423 15:29:01
"The horizontal line is always as long as necessary to reach the left and right end of both numbers (and operators) directly below and above it." 

neverhopeless:
20180417 13:12:12
Finally made it.!!! :) Without .in and .out file (linked in comments) it is hard to fix the formatting part of this problem. 

badasshackme:
20180405 02:16:22
Dude, who originally posted critical input


andrzej_podo98:
20180219 21:55:12
anyone has TLE with this problem??? time limits in that task are rather big... Last edit: 20180219 21:56:40 

anirudnits:
20180205 20:41:23
AC in 2nd attempt! 

changchiyou:
20180116 13:00:21
after hours i have finished this sXit in 200 lines......read the "Output" description carefully than every thing would be fine.


suresh_aravind:
20180113 18:41:40
If anybody is getting wrong answer when multiplying big numbers, it's because of int overflow. Use long data type and it'll be fine. 

iamsarthakk:
20171205 12:24:14
the compiler is not multiplying numbers correctlty 999999999999999*999999999999999=5074944270305263617 this is what the compiler is giving output by multiplying.How to fix this issue?


p68sharm:
20171124 04:24:38
Very thankful to the person who provided the link for the test cases!! Finally got AC after so long.....!! :) :) Last edit: 20171124 04:24:51 

newb:
20170730 21:53:52
Thanks Vladmir, for the test cases. They helped me catch corner cases. Finally got accepted after 10+ hours of work. 
Added by:  adrian 
Date:  20040508 
Time limit:  5s 
Source limit:  50000B 
Memory limit:  1536MB 
Cluster:  Cube (Intel G860) 
Languages:  All except: NODEJS PERL6 VB.NET 
Resource:  ACM Central European Programming Contest, Prague 2000 