ARITH - Simple Arithmetics
One part of the new WAP portal is also a¬†calculator computing expressions with very long numbers. To make the output look better, the result is formated the same way as is it usually used with manual calculations.
Your task is to write the core part of this calculator. Given two numbers and the requested operation, you are to compute the result and print it in the form specified below. With addition and subtraction, the numbers are written below each other. Multiplication is a¬†little bit more complex: first of all, we make a¬†partial result for every digit of one of the numbers, and then sum the results together.
There is a¬†single positive integer T on the first line of input (equal to about 1000). It stands for the number of expressions to follow. Each expression consists of a¬†single line containing a¬†positive integer number, an¬†operator (one of +, - and *) and the second positive integer number. Every number has at most 500¬†digits. There are no spaces on the line. If the operation is subtraction, the second number is always lower than the first one. No number will begin with zero.
For each expression, print two lines with two given numbers, the second number below the first one, last digits (representing unities) must be aligned in the same column. Put the operator right in front of the first digit of the second number. After the second number, there must be a¬†horizontal line made of dashes (-).
For each addition or subtraction, put the result right below the horizontal line, with last digit aligned to the last digit of both operands.
For each multiplication, multiply the first number by each digit of the second number. Put the partial results one below the other, starting with the product of the last digit of the second number. Each partial result should be aligned with the corresponding digit. That means the last digit of the partial product must be in the same column as the digit of the second number. No product may begin with any additional zeros. If a¬†particular digit is zero, the product has exactly one digit -- zero. If the second number has more than one digit, print another horizontal line under the partial results, and then print the sum of them.
There must be minimal number of spaces on the beginning of lines, with respect to other constraints. The horizontal line is always as long as necessary to reach the left and right end of both numbers (and operators) directly below and above it. That means it begins in the same column where the leftmost digit or operator of that two lines (one below and one above) is. It ends in the column where is the rightmost digit of that two numbers. The line can be neither longer nor shorter than specified.
Print one blank line after each test case, including the last one.
4 12345+67890 324-111 325*4405 1234*4
12345 +67890 ------ 80235 324 -111 ---- 213 325 *4405 ----- 1625 0 1300 1300 ------- 1431625 1234 *4 ---- 4936Warning: large Input/Output data, be careful with certain languages.
Last edit: 2015-11-19 00:24:03
I'm done with coding, tried many cases of input even with 500 digit number, and getting output while running on cmd. but here when I'm submitting my solution it is giving me runtime error here.
i guess... nobody can solve this question in less than 250 lines in c++ :p
wast of time
I can't get the format to match. Read all the links regarding the output formats. But still can't figure out. The person to add this problem should take a serious note regarding the data of the problem. Many people are complaining about it, but he has nothing to do with it.
@candide found a great case. Check 9999*99 as well. Make sure to do a DIFF on your output! No trailing spaces!
500 digits... cannot use int
aww... I don't know why I got WA :(( I've used FPC :v it got correct output on ideone...
Careful with the dashes !