## CPTTRN1 - Character Patterns (Act 1)

Using two characters: . (dot) and * (asterisk) print a chessboard-like pattern. The first character printed should be * (asterisk).

### Input

You are given t < 100 - the number of test cases and for each of the test cases two positive integers: l - the number of lines and c - the number of columns in the pattern (l, c < 100).

### Output

For each of the test cases output the requested pattern (please have a look at the example). Use one line break in between successive patterns.

### Example

```Input:
3
3 1
4 4
2 5

Output:
*
.
*

*.*.
.*.*
*.*.
.*.*

*.*.*
.*.*.
```

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 < Previous 1 2 3 4 Next > vicc255: 2018-03-17 19:12:09 I thought the question was wrong but it's correct.See odd and even similarity between row no. and column no. Good luck. jairaj_sahgal: 2018-03-10 15:18:23 I love it secret_santa1: 2017-12-20 15:57:16 Approach-1)Draw a chessboard and enter the given values i.e. fill the chessboard with "." and "*"(say 4*4 chessboard) 2)Observe the position of all the asterisk (or dots) and figure out the pattern. 3)Hint: Odd/even positions. Note-All given input & output are correct. vinay11vishu: 2017-11-13 20:08:34 @vshantam I am able to get the pattern correctly, but with my own input. Logic seems to be right but i am missing something with their inputs. Can you mail me your solution at karmavinayvkv@gmail.com.. Would be great help.. vshantam: 2017-11-12 10:40:24 @vinay11vishu The idea i implemented was to run two for loops and when (i %2==0 and j%2==0) or (i%2!=0 and j%2!=0) then print '*' or else print '.' where i and j depends on input on each line . works for me perfectly . Last edit: 2017-11-12 10:42:33 vinay11vishu: 2017-10-29 11:17:16 Can anybody explain me how the input should be given to this program ?? Last edit: 2017-10-29 12:35:27 imtiaz_mehedi: 2017-08-30 19:35:31 i have done it..it shows the right output but here it said it's wrong Last edit: 2017-08-30 19:35:57 deepk_keshri: 2017-08-21 19:48:42 if line no. is odd,odd position have * and if line is even ,even position will '*' mesakh123: 2017-08-09 08:38:43 there is two conditions and two sub conditions 1.if odd number lines: a. if odd number word(character)position b.if even number word(character)position 2.if even number lines: a. if odd number word(character)position b.if even number word(character)position that's how i solve the problem Last edit: 2017-08-09 08:39:46 dungtungmtp: 2017-04-06 20:37:30 ex1 and ex2 i can't know

 Added by: kuszi Date: 2012-09-03 Time limit: 0.25s Source limit: 50000B Memory limit: 1536MB Cluster: Cube (Intel G860) Languages: All except: ASM64