DIVSUM  Divisor Summation
Given a natural number n (1 <= n <= 500000), please output the summation of all its proper divisors.
Definition: A proper divisor of a natural number is the divisor that is strictly less than the number.
e.g. number 20 has 5 proper divisors: 1, 2, 4, 5, 10, and the divisor summation is: 1 + 2 + 4 + 5 + 10 = 22.
Input
An integer stating the number of test cases (equal to about 200000), and that many lines follow, each containing one integer between 1 and 500000 inclusive.
Output
One integer each line: the divisor summation of the integer given respectively.
Example
Sample Input: 3 2 10 20 Sample Output: 1 8 22
Warning: large Input/Output data, be careful with certain languages
hide comments
ramini1996:
20180206 13:07:54
AC in ONE GO !!! Last edit: 20180206 13:08:23 

payal2621:
20180113 13:08:11
a nyc problem


dunjen_master:
20171230 14:53:54
https://mathschallenge.net/library/number/sum_of_divisors...... this could help!! 

karthik1997:
20171228 09:41:25
Use Sieve for pre computation and solve each query in O(1) .Dont Forget to use long. you'll surely endup with fastest submission :) 0.00s Last edit: 20171228 09:54:07 

pranaykhin1999:
20171219 13:13:15
why i am getting time limit exceeded??


jvjplus:
20171216 13:54:55
remember: sqrt(x)*sqrt(x)!=x vs (int)sqrt(x)*(int)sqrt(x)==x 

guilheramos:
20171206 14:42:31
Somebody solve this problem using python? 

yashasvi_spoj:
20171203 08:35:43
AC?? Help What is this?


kilojewels:
20171201 12:27:13
can anyone help me understand hoow to use stdin.read() in python 

gopal_05:
20171106 04:14:17
why are we taking square root of n ? 
Added by:  Neal Zane 
Date:  20040610 
Time limit:  3s 
Source limit:  5000B 
Memory limit:  1536MB 
Cluster:  Cube (Intel G860) 
Languages:  All 
Resource:  Neal Zane 