FCTRL  Factorial
The most important part of a GSM network is so called Base Transceiver Station (BTS). These transceivers form the areas called cells (this term gave the name to the cellular phone) and every phone connects to the BTS with the strongest signal (in a little simplified view). Of course, BTSes need some attention and technicians need to check their function periodically.
ACM technicians faced a very interesting problem recently. Given a set of BTSes to visit, they needed to find the shortest path to visit all of the given points and return back to the central company building. Programmers have spent several months studying this problem but with no results. They were unable to find the solution fast enough. After a long time, one of the programmers found this problem in a conference article. Unfortunately, he found that the problem is so called "Travelling Salesman Problem" and it is very hard to solve. If we have N BTSes to be visited, we can visit them in any order, giving us N! possibilities to examine. The function expressing that number is called factorial and can be computed as a product 1.2.3.4....N. The number is very high even for a relatively small N.
The programmers understood they had no chance to solve the problem. But because they have already received the research grant from the government, they needed to continue with their studies and produce at least some results. So they started to study behaviour of the factorial function.
For example, they defined the function Z. For any positive integer N, Z(N) is the number of zeros at the end of the decimal form of number N!. They noticed that this function never decreases. If we have two numbers N_{1}<N_{2}, then Z(N_{1}) <= Z(N_{2}). It is because we can never "lose" any trailing zero by multiplying by any positive number. We can only get new and new zeros. The function Z is very interesting, so we need a computer program that can determine its value efficiently.
Input
There is a single positive integer T on the first line of input (equal to about 100000). It stands for the number of numbers to follow. Then there are T lines, each containing exactly one positive integer number N, 1 <= N <= 1000000000.
Output
For every number N, output a single line containing the single nonnegative integer Z(N).
Example
Sample Input:
6 3 60 100 1024 23456 8735373
Sample Output:
0 14 24 253 5861 2183837
hide comments
saeidm:
20170205 16:28:34
@siddhartha786 calculate number of zeros at the end of n factorial(n!) 

siddhartha786:
20170120 21:15:27
i don't understand the question please help


harshit2202:
20170117 13:50:18
Test cases for 1024 and 23456 are wrong 

scorpion_ajay:
20161220 12:01:26
AC in one go, easy to implement, just get the logic ready in your mind ;) 

nolex:
20161211 15:44:33
Can this be done in 0.0s?


soodan:
20161203 07:55:17
just think how can we create zeros and ur ques is solved!! 

tushar091:
20161112 10:05:32
Last edit: 20161112 10:07:37 

hari123:
20161111 06:33:04
How to download all problems within one click?


vaibhav_06:
20161005 15:19:34
AC in one go.... 

fahim_ferdous:
20160928 15:13:39
I am thinking about using recursion. Is it a good idea? Because the tag is math :/ 
Added by:  adrian 
Date:  20040509 
Time limit:  6s 
Source limit:  50000B 
Memory limit:  1536MB 
Cluster:  Cube (Intel G860) 
Languages:  All except: NODEJS PERL6 VB.NET 
Resource:  ACM Central European Programming Contest, Prague 2000 