HASHIT  Hash it!
Your task is to calculate the result of the hashing process in a table of 101 elements, containing keys that are strings of length at most 15 letters (ASCII codes 'A',...,'z'). Implement the following operations:
 find the index of the element defined by the key (ignore, if no such element),
 insert a new key into the table (ignore insertion of the key that already exists),
 delete a key from the table (without moving the others), by marking the position in table as empty (ignore nonexisting keys in the table)
When performing find, insert and delete operations define the following function:
integer Hash(string key),
which for a string key=a_{1}...a_{n} returns the value:
Hash(key)=h(key) mod 101, where
h(key)=19 *(ASCII(a_{1})*1+...+ASCII(a_{n})*n).
Resolve collisions using the open addressing method, i.e. try to insert the key into the table at the first free position: (Hash(key)+j^{2}+23*j) mod 101, for j=1,...,19.
After examining of at least 20 table entries, we assume that the insert operation cannot be performed.
Input
t [the number of test cases <= 100]
n_{1} [the number of operations (one per line)[<= 1000]
ADD:string
[or]
DEL:string
[other test cases, without empty lines betwee series]
Output
For every test case you have to create a new table, insert or delete keys, and write to the output:
the number of keys in the table [first line]
index:key [sorted by indices]
Example
Input: 1 11 ADD:marsz ADD:marsz ADD:Dabrowski ADD:z ADD:ziemii ADD:wloskiej ADD:do ADD:Polski DEL:od DEL:do DEL:wloskiej Output: 5 34:Dabrowski 46:Polski 63:marsz 76:ziemii 96:z
hide comments
Saif :
20170616 13:59:08
Use this test case:


kspoj:
20170616 08:57:40
Guys, I'm stuck, my code is running fine with most spoj toolkit testcases... But I'm getting WA...


rishi_devan:
20170501 14:40:08
Straightforward ! 

cake_is_a_lie:
20170306 14:46:25
Not double inserting existing items can become problematic after deletions, so be careful! Cost me a lot of WAs. 

vengatesh15:
20170213 08:47:28
There should be a blank line after every test case .. that cost me 2WA 

samnik:
20170212 07:41:58
can anyone help me working for test cases but still getting WA


Bartosz:
20161023 13:15:46
Empty string is also considered to be a valid key, and it have to be put on the position 0. It cost me few WAs to realize that. Last edit: 20161023 13:43:45 

gautam:
20160806 15:40:10
yeah....ac.....!!!! 

souravjaiswal:
20160705 20:58:17
guys just use http://spojtoolkit.com/ to get extra test cases. 

KD :
20160607 09:06:09
AC after 5 WA ....be careful about the deletion and insertion of same elements multiple time: 
Added by:  mima 
Date:  20040601 
Time limit:  3s 
Source limit:  50000B 
Memory limit:  1536MB 
Cluster:  Cube (Intel G860) 
Languages:  All except: NODEJS PERL6 VB.NET 
Resource:   