You are given a sequence A[1], A[2], ..., A[N] ( 0 ≤ A[i] ≤ 10^8 , 2 ≤ N ≤ 10^5 ). There are two types of operations and they are defined as follows:

Update:

This will be indicated in the input by a 'U' followed by space and then two integers i and x.

U i x, 1 ≤ i ≤ N, and x, 0 ≤ x ≤ 10^8.

This operation sets the value of A[i] to x.

Query:

This will be indicated in the input by a 'Q' followed by a single space and then two integers i and j.

Q x y, 1 ≤ x < y ≤ N.

You must find i and j such that x ≤ i, j ≤ y and i != j, such that the sum A[i]+A[j] is maximized. Print the sum A[i]+A[j].

Input

The first line of input consists of an integer N representing the length of the sequence. Next line consists of N space separated integers A[i]. Next line contains an integer Q, Q ≤ 10^5, representing the number of operations. Next Q lines contain the operations.

Output

Output the maximum sum mentioned above, in a separate line, for each Query.

Example

Input:
5
1 2 3 4 5
6
Q 2 4
Q 2 5
U 1 6
Q 1 5
U 1 7
Q 1 5

Output:
7
9
11
12

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	ramini1996: 2018-02-02 20:45:41 My 50th !!! AC in ONE GO !!!
	kushagra__k: 2018-01-01 22:55:23 There can be 2 approaches here: 1> Use a structure array for the max and second max 2> A modification of the Range Maximum Query. After getting AC on 1st one, go for the second one. :)
	vijayrit: 2017-12-20 00:36:46 Please do take sufficienty large array for the tree. Costed me four SIGSEGV errors.
	rishabhm123: 2017-12-17 18:54:04 AC in one go..Simple Segment tree with a slight variation of range min
	the_phoenixx: 2017-12-15 16:30:41 Simple segment tree implementation!!
	grylls: 2017-11-11 08:53:54 Nice Question...AC in one GO:)
	ramprosad: 2017-10-30 06:40:43 Input limit 10^8 , but for integer data type verdict is runtime error ??? What's amaging!!!!!
	vicky_1998: 2017-10-29 06:29:18 AC IN ONE GO!!! Was an easy one, added experience with segment tree though
	da_201501181: 2017-09-14 11:52:22 AC in ONE GO..!!! Nice implementation category question
	VENUKANT SAHU: 2017-09-12 13:28:16 AC in one go :)