LABYR1 - Labyrinth
The northern part of the Pyramid contains a very large and complicated labyrinth. The labyrinth is divided into square blocks, each of them either filled by rock, or free. There is also a little hook on the floor in the center of every free block. The ACM have found that two of the hooks must be connected by a rope that runs through the hooks in every block on the path between the connected ones. When the rope is fastened, a secret door opens. The problem is that we do not know which hooks to connect. That means also that the neccessary length of the rope is unknown. Your task is to determine the maximum length of the rope we could need for a given labyrinth.
The input consists of T test cases. The number of them (T) is given on
the first line of the input file.
Each test case begins with a line containing two integers C and R
(3 <= C,R <= 1000) indicating the number of columns and rows. Then
exactly R lines follow, each containing C characters. These characters
specify the labyrinth. Each of them is either a hash mark (
#) or a period
.). Hash marks represent rocks, periods are free blocks. It is
possible to walk between neighbouring blocks only, where neighbouring
blocks are blocks sharing a common side. We cannot walk
diagonally and we cannot step out of the labyrinth.
The labyrinth is designed in such a way that there is exactly one path between any two free blocks. Consequently, if we find the proper hooks to connect, it is easy to find the right path connecting them.
Your program must print exactly one line of output for each test case. The
line must contain the sentence
Maximum rope length is X." where Xis the
length of the longest path between any two free blocks, measured in blocks.
Sample Input: 2 3 3 ### #.# ### 7 6 ####### #.#.### #.#.### #.#.#.# #.....# ####### Sample output: Maximum rope length is 0. Maximum rope length is 8.Warning: large Input/Output data, be careful with certain languages
|Cluster:||Cube (Intel Pentium G860 3GHz)|
|Resource:||ACM Central European Programming Contest, Prague 1999|
my first ac in one go , finally
Awesome Question (BFS+BFS) "Maja aa gaya Tel Laga Ke" .... :-)
maja aa gaya tel laga k:)
very easy BFS+BFS :)
17 wa,now got ac...o(∩∩)o...use dfs or bfs,not esay
i hate c++14 compiler gives me 4 compilation error .. wtf y? :(
After 3 wa finally AC
Giving Runtime Error!
"there is exactly one path between any two free blocks". Does this means that there will be only one connected component (island) ?
sometimes something easy may also be misleading :-P