MULTQ3 - Multiples of 3
There are N numbers a[0], a[1] ... a[N - 1]. Initially all are 0. You have to perform two types of operations :
- Increase the numbers between indices A and B (inclusive) by 1. This is represented by the command "0 A B"
- Answer how many numbers between indices A and B (inclusive) are divisible by 3. This is represented by the command "1 A B".
Input
The first line contains two integers, N and Q. Each of the next Q lines are either of the form "0 A B" or "1 A B" as mentioned above.
Output
Output 1 line for each of the queries of the form "1 A B" containing the required answer for the corresponding query.
Sample
Input: 4 7 1 0 3 0 1 2 0 1 3 1 0 0 0 0 3 1 3 3 1 0 3 Output: 4 1 0 2
Constraints
1 ≤ N ≤ 100000
1 ≤ Q ≤ 100000
0 ≤ A ≤ B ≤ N - 1
hide comments
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shady51:
2018-01-10 12:04:32
Rectify the time limit for Java. I am using segment tree with lazy propagation with fast input/output, and still getting TLE, used the same approach in C++14 and got accepted. Last edit: 2018-01-10 13:35:57 |
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code_aim:
2017-09-29 16:43:28
Good one!! |
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vishakha14:
2017-08-17 15:08:56
Spoj is just too harsh for java users. TLE despite O(n + qlogn) + Fast I/O soln. |
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shubham_7616:
2017-06-14 18:00:23
Take size of array to be 10^6 and size of seg tree to be 4*(10^6).
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sas1905:
2017-06-05 21:08:59
Segment+lazy.. |
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lord_poseidon:
2017-05-29 11:44:31
AC in one go
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akshayvenkat:
2017-05-25 06:47:45
Segment tree, lazy propogation , scanf+printf works just fine. Simple adhoc trick is the only optimization required. |
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rajeev_899:
2017-03-21 15:59:11
enjoyed solving this :) easy one AC in one go |
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shahzada:
2017-03-18 13:02:49
Internal Error->RE->AC (Easy though) |
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iam_ss:
2017-03-16 20:01:38
Easy question and a good practice for lazy propagation using Segmented Trees. |
| Added by: | Varun Jalan |
| Date: | 2010-09-12 |
| Time limit: | 1s |
| Source limit: | 50000B |
| Memory limit: | 1536MB |
| Cluster: | Cube (Intel G860) |
| Languages: | All except: NODEJS OBJC VB.NET |
| Resource: | own problem |
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