SPOJ.com - Problem NDIVPHI

NDIVPHI - N DIV PHI_N

#math #number-theory

Given an integer N <= 10⁴⁰ find the smallest m <= N such that m/phi(m) is maximum.

N₁
N₂
.
.
.
N₂₀

m₁
m₂
.
.
.
m₂₀

Input:
10
.
.

Output:
6
.
.

< Previous 1 2 Next >

	zakir068: 2020-03-14 07:25:00 there are 20 inputs
	ubot: 2019-03-13 03:25:03 i am comparing numbers after each successive multiplication, but the given order is of 10^40, which makes it impossible for me to compare, what is the workaround for that? Last edit: 2019-03-13 03:29:36
	infinity_01: 2018-08-26 16:46:07 the input format is not specified correctly Last edit: 2018-09-01 16:02:07
	akshat_pat: 2018-01-04 11:49:38 Finally AC ! silly mistake.Used < intsead of <=
	sheldont: 2017-06-25 11:49:47 cakewalk with python..
	invincible_rm: 2016-06-26 13:29:49 Awesome !! Just Take a deep breathe n think a strategy to procede Its cousin can be found here: https://projecteuler.net/problem=70
	Ayush Agarwal: 2014-09-28 18:31:20 python is awesome
	Bharath Reddy: 2014-09-24 05:40:08 Take care of the case when n = 1
	saket diwakar: 2013-01-26 00:45:13 python is awesome....:)
	Samuel Shen: 2012-06-03 13:10:03 i have checked everything...its giving me correct answers for all n.....and time limit is also within 1 sec....even then TLE.....anyone plz help....

Added by:	Frank Rafael Arteaga
Date:	2010-04-22
Time limit:	1s
Source limit:	50000B
Memory limit:	1536MB
Cluster:	Cube (Intel G860)
Languages:	All except: NODEJS OBJC PERL6 SQLITE VB.NET
Resource:	ProjectEuler