PARTY  Party Schedule
You just received another bill which you cannot pay because you lack the money.
Unfortunately, this is not the first time to happen, and now you decide to investigate the cause of your constant monetary shortness. The reason is quite obvious: the lion's share of your money routinely disappears at the entrance of party localities.
You make up your mind to solve the problem where it arises, namely at the parties themselves. You introduce a limit for your party budget and try to have the most possible fun with regard to this limit.
You inquire beforehand about the entrance fee to each party and estimate how much fun you might have there. The list is readily compiled, but how do you actually pick the parties that give you the most fun and do not exceed your budget?
Write a program which finds this optimal set of parties that offer the most fun. Keep in mind that your budget need not necessarily be reached exactly. Achieve the highest possible fun level, and do not spend more money than is absolutely necessary.
Input
The first line of the input specifies your party budget and the number n of parties.
The following n lines contain two numbers each. The first number indicates the entrance fee of each party. Parties cost between 5 and 25 francs. The second number indicates the amount of fun of each party, given as an integer number ranging from 0 to 10.
The budget will not exceed 500 and there will be at most 100 parties. All numbers are separated by a single space.
There are many test cases. Input ends with 0 0.
Output
For each test case your program must output the sum of the entrance fees and the sum of all fun values of an optimal solution. Both numbers must be separated by a single space.
Example
Sample input: 50 10 12 3 15 8 16 9 16 6 10 2 21 9 18 4 12 4 17 8 18 9 50 10 13 8 19 10 16 8 12 9 10 2 12 8 13 5 15 5 11 7 16 2 0 0 Sample output: 49 26 48 32
hide comments
vanvinhbk94:
20170217 14:39:18
AC in one go!! use 0/1 Knapsack ^ ^ 

ankit1cool:
20170209 10:41:06
for beginner ,try to do with recursion will be a great learning experience 

gautam:
20170130 11:24:24
good one ..!! 

tni_mdixit:
20170123 21:51:43
no need for any backtracking or last row check...order of the loops will do!


tni_mdixit:
20170122 21:50:33
Last edit: 20170123 21:51:59 

govindgupta:
20170111 12:12:58
easy one!!! 01 knapsack


epsilonalpha:
20161220 19:01:33
Learnt about 01 Knapsack. First I tried backtracking but got a wrong answer, not sure why. Then as usual, the comments were very helpful. :)


akashranjan28:
20161213 12:41:20
AC bottom up approach...


rohit1507:
20161129 11:46:32
0/1 Knapsack. But do check for minimum money to be used.


kushalanand:
20161104 22:21:40
0.0 seconds. WOW. AC in one go.

Added by:  Patryk Pomykalski 
Date:  20040701 
Time limit:  3s 
Source limit:  50000B 
Memory limit:  1536MB 
Cluster:  Cube (Intel G860) 
Languages:  All 
Resource:  Swiss Olympiad in Informatics 2004 