PRINTSPIRAL  Printing Spiral Digits
You are given two integers, the number of Rows(N) and the number of Columns(M) of a matrix. Your task is to print numbers from 1 to N*M in a spiral form. The spiral number begins from the topleft corner, continues to the top right corner, then bottom right corner, then goes to bottom left corner, and goes back up to 1 row below the top row, and then the pattern continues until the matrix is full. If the largest number is more than 9, then print 0 before the number if the number is less than 10 (see input examples for clarification).
Input
Input starts with an integer T (1 ≤ T ≤ 20), denoting the number of test cases. Each of the test cases consists of integer N and M (1 ≤ N*M ≤ 99), denoting the number of rows and columns of the matrix.
Output
For each case print "Case X:", where X (1 ≤ X ≤ T) is the case number, followed by a newline. There must be no trailing spaces at the end of printed lines, neither empty characters. After that, print the sets of number in spiral form. Print a newline after each testcase.
Example
Input: 3 4 5 3 3 2 3 Output: Case 1: 01 02 03 04 05 14 15 16 17 06 13 20 19 18 07 12 11 10 09 08 Case 2: 1 2 3 8 9 4 7 6 5 Case 3: 1 2 3 6 5 4
hide comments
dpdocs21:
20161202 10:13:28
It's just trailing spaces which were causing problem for me and not the extra line at the end. Thanks @last_phoenix 

silence026:
20161201 16:47:26
Don't print an extra "\n" in the end.


last_phoenix:
20160614 16:39:58
Be very careful with trailing spaces at the end of printed lines.... 
Added by:  hanstan 
Date:  20160510 
Time limit:  1s 
Source limit:  50000B 
Memory limit:  1536MB 
Cluster:  Cube (Intel G860) 
Languages:  All except: ASM64 GOSU JSMONKEY 
Resource:  Self 