TREEORD  Tree _order
Description
A tree is a connected acyclic graph.
A binary tree is a tree for which each node has a left child, a right child, both, or neither, e.g.
1 / \ 2 3 / \ \ 4 5 6
There are three common ways to recursively traverse such a tree.
 Preorder: parent, left subtree, right subtree
 Postorder: left subtree, right subtree, parent
 Inorder: left subtree, parent, right subtree
Given preorder, postorder, and inorder traversals, determine if they can be of the same binary tree.
For example,
1 2 4 5 3 6 4 5 2 6 3 1 4 2 5 1 3 6are the preorder, postorder, and inorder traversals of the tree above.
But
1 2 4 5 3 6 4 5 2 6 1 3 4 2 5 1 6 3cannot be the preorder, postorder, and inorder tranversals of the same binary tree.
Input
The first line is the number of nodes in each traversal, 0 < N <= 8000.
The second line is the N space seperated nodes of the preorder traveral.
The third line is the N space separated nodes of the postorder traversal.
The fourth line is the N space separated nodes of the inorder traversal.
The second line is the N space seperated nodes of the preorder traveral.
The third line is the N space separated nodes of the postorder traversal.
The fourth line is the N space separated nodes of the inorder traversal.
Each traversal is a sequence of the nodes, numbered 1 to N, without repitition.
Output
Print "yes" if all three traversals can be of the same tree, and "no" otherwise.
Input  Input 

6 1 2 4 5 3 6 4 5 2 6 3 1 4 2 5 1 3 6 
6 1 2 4 5 3 6 4 5 2 6 1 3 4 2 5 1 6 3 
Output  Output 
yes 
no 
hide comments
Pranv Gupta:
20170331 11:37:21
nice question, but wondering if there is only ONE testcase of this problem 

deerishi:
20161022 23:43:56
MY 100th! 0.00 sec.!! Funny thing : With and without Tree construction with Fast IO accepted in 0.00s !! Without tree construction is cooler though. Last edit: 20161023 00:57:34 

cnexans:
20160804 06:57:48
I found it tricky. Finally AC. 

kartikay singh:
20160630 20:50:36
Nice problem :)


naufalpf:
20160409 14:20:36
y


sumbayak_ae:
20160407 14:12:42
Sesi Lab, ez :v Last edit: 20160407 14:27:26 

sumbayak_ae:
20160407 14:09:54
AC in one go. Nice problem. Think of recursion ;D 

Archit Gupta:
20160226 11:04:52
AC in first attempt easy prob 150th on spoj! 

:.Mohib.::
20160102 12:03:35
Like it...!! 

kejriwal:
20151010 19:22:59
nice and elegant (: !! 
Added by:  BYU Admin 
Date:  20140223 
Time limit:  0.5s3s 
Source limit:  50000B 
Memory limit:  1536MB 
Cluster:  Cube (Intel G860) 
Languages:  All except: ASM64 