SPOJ.com - Problem RGB7172

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RGB7172 - Гурвалжны хэлбэр

Гурвалжны 3 тал нь бүхэл тоогоор өгөгдсөн бол хэлбэрийг нь тодорхойл. Хэлбэр нь тэгш өнцөгт, хурц өнцөгт, мохоо өнцөгтийн аль нэг байна.

Input

Нэг мөрөнд гурвалжны 3 тал зайгаар тусгаарлагдан натурал тоонуудаар өгөгдөнө.

Output

Гурвалжин нь тэгш өнцөгт бол "Right", мохоо өнцөгт бол "Obtuse", хурц өнцөгт бол "Acute" гэж тус тус хэвлэнэ.

Example

Input:
3 4 5

Output:
Right

Submit solution!

Нэмсэн:	Bataa
Огноо:	2013-01-14
Хугацааны хязгаарлалт:	1s
Эх кодын хэмжээний хязгаарлалт:	50000B
Memory limit:	1536MB
Cluster:	Cube (Intel G860)
Програмчлалын хэлүүд:	ADA95 ASM32 BASH BF C NCSHARP CSHARP C++ 4.3.2 CPP C99 CLPS LISP sbcl LISP clisp D ERL FORTRAN HASK ICON ICK JAVA JS-RHINO JULIA LUA NEM NICE OCAML PAS-GPC PAS-FPC PERL PHP PIKE PRLG-swi PYTHON PYPY3 PYTHON3 RUBY SCALA SCM guile ST TCL WHITESPACE

hide comments

2024-01-16 05:59:26
#include <iostream>
using namespace std;
int main ()
{
int a, b, c, urt, d, e;
cin >> a >> b >> c;
if ( a >= b && a >= c){
urt = a;
d = b;
e = c;
}
if ( b >= a && b >= c){
urt = b;
d = a;
e = c;
}
if ( c >= a && c >= b){
urt = c;
d = a;
e = b;
}

if ( urt * urt == d * d + e * e ){
cout << "Right" << endl;
}else if (urt * urt > d * d + e * e) {
cout << "Obtuse" << endl;
}else {
cout << "Acute" << endl;
}

return 0;
}

2024-01-09 09:26:58
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣀⣀⣀⣀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢀⡀⠀⠀⠀⠀⢠⠊⠁⠀⠀⠈⠉⠒⢄⠀⠀⠀⠀⣀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣿⣷⣄⡀⠀⣴⡿⠛⢶⣄⠀⠀⣠⡴⠾⢧⠀⢀⣼⣿⠆⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠉⠻⣿⣿⡿⣿⠛⣿⡧⠸⣿⣿⡷⡶⠠⠏⠁⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢠⡟⠉⠛⢛⣚⡉⠀⠀⠈⠛⠋⠁⠸⡄⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢸⣦⣤⣴⣿⠿⣷⣤⡤⠤⠖⠣⡀⠀⡇⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣸⣁⣿⡿⢦⣀⠀⠀⠀⠀⠀⠀⠈⠓⢿⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣴⣿⣿⣿⣿⣿⣿⠛⠛⠉⠉⠉⠀⠀⠀⠘⢤⣀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢀⣼⣿⣿⣿⣿⡻⣿⠿⠛⠀⠀⠀⠀⠀⠀⠀⠀⠀⠈⠑⠲⠦⠤⣄⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣠⣶⣿⣿⣿⣿⣿⣿⣿⣿⣶⣄⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠉⠑⠢⡀⠀⠀⠀⠀⠀⠀
⠀⠀⠀⠀⠀⠀⠀⢀⣠⠴⠒⠓⠛⢻⣿⡿⠿⠛⠉⠻⢿⣿⣿⠿⠿⠛⠓⠋⠉⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠘⢆⠀⠀⠀⠀⠀
⠀⠀⠀⠀⠀⢀⣶⠏⣼⠀⠀⠀⠀⠈⠉⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢧⠀⠀⠀⠀
⠀⠀⠀⠀⣠⣿⣯⡼⠈⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢈⡇⠀⠀⠀
⠀⠀⠀⣰⣿⣿⣿⣿⣷⣶⣾⣇⣇⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢸⣄⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢀⣿⣿⣦⣤⣤⡠⠀⣤⣿⣧⠀⠀⠀
⠀⠀⠀⣿⣿⣿⡿⢳⠶⢉⡿⣿⣜⡖⡄⠀⠀⠀⠀⠀⠀⠀⠀⠀⣾⣼⣄⡀⠀⠀⠀⠀⠀⢀⣤⣶⣿⣿⡿⡟⠫⡭⠽⣾⣟⡋⠀⠀⠀⠀
⠀⣀⣴⣿⣿⠿⠟⠁⣠⠞⢠⣿⣿⣿⣿⣧⣄⣀⣀⠀⠀⣀⣤⡶⢿⣿⣿⣿⣶⣀⣀⣤⣾⣿⣿⣿⣿⣿⠁⠙⣆⠀⠀⢾⣿⣿⣦⡀⠀⠀
⣿⣿⣿⡿⣿⣷⣠⡾⠃⢠⣿⣿⠿⣿⣿⣿⣿⣿⣿⣷⣾⣿⣿⠅⠺⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⡾⣆⠈⢷⡄⣠⣾⣿⣿⣿⣷⣄
⡿⣿⣿⣿⣎⣿⡿⠀⣰⣿⣿⣿⣷⡈⢻⣿⣿⣿⣿⣿⣟⡉⠀⠀⠀⠈⠉⠛⢿⣿⣿⣿⣿⣿⣿⠟⣱⣾⣿⣿⣇⠀⢹⣿⢏⣾⣿⣿⣿⡟
⣷⣿⣿⡿⢏⣿⡇⢀⣿⣿⣿⣿⣿⡛⠀⠈⢻⣿⣿⠟⠛⠛⠁⠀⠀⠀⠀⠀⠉⠹⣿⣿⣿⡏⠁⠀⢿⣿⣿⣿⣿⡇⠘⣿⣼⢿⣿⣿⣾⣿
⢹⣿⡿⣿⣿⡿⢡⠞⠁⠽⢿⣿⡇⠀⠀⢠⣞⢿⣄⣤⣀⣀⠀⠀⢸⣀⠀⠀⠀⡀⠈⠉⠙⢧⡀⠀⠀⣿⣿⠟⠙⠻⣆⠻⣿⣿⣿⣿⣿⠋
⢸⣿⣿⣿⣿⣧⣿⣦⣤⣀⣸⣿⠁⠀⢰⠿⡿⣿⡿⠿⠿⠿⠷⣄⠈⠿⠛⠻⠿⢿⣶⣄⣀⣾⣿⡀⠀⣻⣷⣀⣠⣴⣿⣆⣿⣿⣿⣿⣿⠀
⣿⣿⣿⣿⣿⣿⡿⠋⠈⠉⠉⠃⢸⣶⣾⠀⠀⣹⣇⠀⣆⠀⠀⠀⣶⠀⠀⠀⣰⢀⢿⠉⠉⠉⠙⣷⢾⡟⠛⠉⠉⠈⠻⣿⣿⣿⣿⣿⣿⠀
⢸⣿⣻⣿⣿⣯⣀⡀⠀⠀⢀⣠⢘⣿⣿⣶⠀⢻⣿⣿⣿⣧⣀⣀⣿⣦⣀⡐⢓⣺⣿⠀⠀⠀⣵⡆⢸⡷⣄⣀⣐⢀⣀⣸⣿⣿⣿⣿⡇⠀
⣼⣿⣛⣿⣿⣿⠉⠉⠉⠉⠉⠀⣸⣿⣿⡇⠀⢲⣿⠉⠉⠉⠳⣴⠋⠙⠻⣿⣿⣿⡇⠀⠀⣿⣿⠇⠀⣇⠀⠀⠉⠉⠉⢹⣿⣿⣿⣿⡇⠀
⠉⠛⢿⣿⡿⠿⡦⠀⠀⠀⠀⠀⣿⣯⣽⣇⠐⣿⣿⣿⢷⠦⡄⠀⠀⠀⢠⣿⣿⠟⠁⠀⣰⣿⡟⠀⠀⠘⢧⠲⠤⠤⠴⠿⠿⣿⣿⣿⡇⠀

2023-12-05 09:22:21
#include<iostream>

using namespace std;

int main(){
int a,b,c;

cin>>a>>b>>c;

if(c>a && c>b){
if (c*c>a*a+b*b) cout<<"Obtuse";
if (c*c==a*a+b*b) cout<<"Right";
if (c*c<a*a+b*b) cout<<"Acute";
}
if(a>c && a>b){
if (a*a>c*c+b*b) cout<<"Obtuse";
if (a*a==c*c+b*b) cout<<"Right";
if (a*a<c*c+b*b) cout<<"Acute";
}
if(b>c && b>a){
if (b*b>a*a+c*c) cout<<"Obtuse";
if (b*b==a*a+c*c) cout<<"Right";
if (b*b<a*a+c*c) cout<<"Acute";
}
}

2023-12-05 09:22:19
#include<iostream>

using namespace std;

int main(){
int a,b,c;

cin>>a>>b>>c;

if(c>a && c>b){
if (c*c>a*a+b*b) cout<<"Obtuse";
if (c*c==a*a+b*b) cout<<"Right";
if (c*c<a*a+b*b) cout<<"Acute";
}
if(a>c && a>b){
if (a*a>c*c+b*b) cout<<"Obtuse";
if (a*a==c*c+b*b) cout<<"Right";
if (a*a<c*c+b*b) cout<<"Acute";
}
if(b>c && b>a){
if (b*b>a*a+c*c) cout<<"Obtuse";
if (b*b==a*a+c*c) cout<<"Right";
if (b*b<a*a+c*c) cout<<"Acute";
}
}

2023-10-20 17:21:56
#include <stdio.h>
#include <stdlib.h>

int cmd (const void * a, const void * b) {
return ( *(int*)a - *(int*)b );
}

int main()
{
int a[3];

for (int i = 0; i < 3; i++)
{
scanf("%d", &a[i]);
}

qsort(a, 3, sizeof(int), cmd);

for(int i = 0; i < 3; i++)
{
a[i] = a[i] * a[i];
}

a[0] = a[0] + a[1];

if (a[2] == a[0])
{
printf("Right");
}
else if(a[2] > a[0]){
printf("Obtuse");
}
else{
printf("Acute");
}

return 0;
}

2023-05-19 02:19:48
#include <iostream>
using namespace std;
int main() {
int a , b , c , d , e , f;
scanf("%d %d %d " , &a , &b ,&c );
if(a < b && c < b){
d=b;
e=a;
f=c;
}
if(a < c && b < c){
d=c;
e=b;
f=a;
}
if(b < a && c < a) {
d=a;
e=c;
f=b;
}
if(e*e + f*f == d*d)printf("Right");
if(e*e + f*f > d*d )printf("Acute");
if(e*e + f*f < d*d )printf("Obtuse");
return 0;
}

2023-05-10 11:08:07
hudla sha

2023-03-15 03:07:37
#include<bits/stdc++.h>
using namespace std;
int main(){
int a,b,c,z,x,d;

cin>>a>>b>>c;

z=a;
x=b;
d=c;
if(b>c&&b>a){
a=b;
b=z;
}

else if(c>b&&c>a){
a=c;
c=z;
}

if(a*a==b*b+c*c) cout<<"Right"<<endl;
else if(a*a>b*b+c*c) cout<<"Obtuse"<<endl;
else if(a*a<b*b+c*c) cout<<"Acute"<<endl;

return 0;
}
huln nie d zoriulav
malaa

2023-02-04 05:51:24
MY SONGS KNOW WHAT YOU DID IN THE DAaAaAaAaAaAaAaARK

2023-01-09 10:12:33
#include<bits/stdc++.h>
using namespace std;
int main()
{
int a,b,c,d,e;
scanf("%d %d %d",&a,&b,&c);
if(a>b && a>c){
if(a*a==(b*b+c*c))
printf("Right");
if(a*a<(b*b+c*c))
printf("Acute");
if(a*a>(b*b+c*c))
printf("Obtuse");
}
if(b>a && b>c)
{
if(b*b==(a*a+c*c))
printf("Right");
if(b*b<(a*a+c*c))
printf("Acute");
if(b*b>(a*a+c*c))
printf("Obtuse");
}
if(c>a && c>b)
{
if(c*c==(a*a+b*b))
printf("Right");
if(c*c<(a*a+b*b))
printf("Acute");
if(c*c>(a*a+b*b))
printf("Obtuse");
}
}

АЛГОРИТМЫН ЦАГААН ТОЛГОЙ

RGB7172 - Гурвалжны хэлбэр

Input

Output

Example