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RGB7231 - Синус нийлбэр 2

sinx+sin2x+sin3x+...+sinnx нийлбэрийг ол.

Input

Бодит тоо x натурал тоо n нэг мөрөнд зайгаар тусгаарлагдан өгөгдөнө.

Output

Нийлбэр. Таслалаас хойш 3 оронгоор нарийвчлалтайгаар гарга.

Example

Input:
0.5 4

Output:
0.872

Нэмсэн:Bataa
Огноо:2013-01-23
Хугацааны хязгаарлалт:1s
Эх кодын хэмжээний хязгаарлалт:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Програмчлалын хэлүүд:ADA95 ASM32 BASH BF C NCSHARP CSHARP C++ 4.3.2 CPP C99 CLPS LISP sbcl LISP clisp D ERL FORTRAN HASK ICON ICK JAVA JS-RHINO JULIA LUA NEM NICE OCAML PAS-GPC PAS-FPC PERL PHP PIKE PRLG-swi PYTHON PYPY3 PYTHON3 RUBY SCALA SCM guile ST TCL WHITESPACE

hide comments
2022-01-23 10:11:37
#include<stdio.h>
#include<math.h>
#include<stdlib.h>
float a,b,c,d,e=0;
int main()
{
scanf("%f%f",&a,&b);
for(c=1; c<=b ; c++)
{
d=pow(sin(a),c);
e=e+d;
}
printf("%.3f",e);
return 0;
}
dahiad tugsuu ah ni bnaa ahaha [copy this]
2021-08-22 03:04:15
suguudl huuln EZ PEAZY LEMON SQUAZY
2019-11-02 06:32:09
#include <cstdio>
#include <cmath>

int main () {
int a , n , i;
double x;
scanf("%lf%d",&x , &n);
double sum = 0;
double l = 1;
for(i = 1 ; i <= n ; i++){
l = l * sin(x);
sum = sum + l;
}
printf("%.3lf" , sum );
}
SUPER
2019-11-02 06:31:50
#include<cstdio>
#include<cmath>
int main(){
int a,n,i;
double x;
scanf("%lf%d", &x , &n);
double sum=0;
double l=1;
for( i=1 ; i<=n ; i++){
l= l* sin(x);
sum= sum + l;
}
printf("%.3lf" , sum);

}
2019-11-02 06:28:56
im wattson legend
2019-11-02 06:26:26
g00d m0rn1ng
2019-11-02 05:36:58
g0dz1lla
2019-11-02 05:36:31
b1rdhunt3r
2019-11-02 05:36:02
lol
2019-10-11 06:05:30
ez
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