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RGB7404 - Давхар давталт 4

Өгөгдсөн тоон тусламжтайгаар жишээн дээрхтэй төстэй тоон хэлбэрийг үүсгэ.

Input

Бүхэл тоо өгөгдөнө.

Output

Жишээн дээрхтэй төстэй тоон хэлбэрийг үүсгэ.

Example

Input:
5
Output:
5
5 4
5 4 3
5 4 3 2
5 4 3 2 1

Нэмсэн:Bataa
Огноо:2013-01-14
Хугацааны хязгаарлалт:1s
Эх кодын хэмжээний хязгаарлалт:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Програмчлалын хэлүүд:ADA95 ASM32 BASH BF C NCSHARP CSHARP C++ 4.3.2 CPP C99 CLPS LISP sbcl LISP clisp D ERL FORTRAN HASK ICON ICK JAVA JS-RHINO JULIA LUA NEM NICE OCAML PAS-GPC PAS-FPC PERL PHP PIKE PRLG-swi PYTHON PYPY3 PYTHON3 RUBY SCALA SCM guile ST TCL WHITESPACE

hide comments
2025-02-19 03:07:21
#include <iostream>
#include <sstream>
#include <string>
#include <cstdlib>
#include <cmath>

using namespace std;

// Headers
string toString (double);
int toInt (string);
double toDouble (string);

int main() {
int i, j, n;

cin >> n;
for (i = n; i >= 1; i--) {
for (j = n; j >= i; j--) {
cout << j;
cout << " ";
}
cout << "" << endl;
}
return 0;
}

// The following implements type conversion functions.
string toString (double value) { //int also
stringstream temp;
temp << value;
return temp.str();
}

int toInt (string text) {
return atoi(text.c_str());
}

double toDouble (string text) {
return atof(text.c_str());
}
2025-02-02 16:32:32
#include<iostream>
using namespace std;
int main (){
int a;
cin>>a;
for(int i=a; i>=1;i--){
for(int j=a; j>=i ; j--)
cout<<j<<" ";
cout<<endl;
}

return 0;
}//zzo amjilt
2024-11-08 11:20:31
#include <iostream>
using namespace std;

int main() {

int a;
cin >> a;
for(int i = a; i >= 1; i--){
for(int j = a; j >= i; j--){
cout << j << " ";
}
cout << endl;
}

return 0;
}
zqoa avo
2024-10-09 12:28:29
#include <iostream>

int main() {
int n;
std::cin >> n;

for (int i = 0; i < n; ++i) {
for (int j = 0; j < n - i; ++j) {
std::cout << (n - j) << " ";
}
std::cout << std::endl;
}


}
2024-06-29 11:43:28
niger
2024-05-20 05:49:49
kjkhj


Last edit: 2024-05-20 05:50:09
2024-05-20 05:47:16
alna shu unsahd bnu
2024-04-28 11:33:08
#include <stdio.h>
int main()
{
int n,i,j;
scanf("%d",&n);
for(i=n;i>=1;i--)
{
for(j=n;j>=i;j--)
printf("%d ",j);
printf("\n");
}
return 0;
}
huuul suga sda nar
2024-04-22 05:42:41
ndd hicel bish nz bandida mongol hel zaj ugurei =)
2024-04-22 05:27:02
+pormnbty6jnmklmGHVcrE
jk6
l=0-2



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