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AMR10C - Square Free Factorization |
You all know about factorization of an integer. Here we want you to factor a number into as few factors as possible. That is easy, you say, just have the number itself, and that will be the smallest number of factors i.e. 1.
But wait, I haven't finished — each of the factors that you find must be square-free. A square-free number, however you factor it, won't have any factor that is a perfect square. Of course, you can never include 1 as a factor.
Input
The first line of input is the number of test cases T. The next T lines each have an integer N.
Output
For each test case, output the smallest number of square-free factors.
Constraints
T ≤ 104
2 ≤ N ≤ 106
Example
Input: 2 6 8 Output: 1 3
Added by: | Varun Jalan |
Date: | 2010-12-13 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |
Resource: | own problem, ICPC Asia regionals, Amritapuri 2010 |
hide comments
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2015-03-29 14:08:14 Madhav
good concept!! |
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2015-01-09 09:32:09 Malinga
Sieve+fast I/O...AC in 1.19 sec |
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2014-12-30 09:35:03 Anubhav Balodhi
Mathematical one ^_^ |
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2014-06-25 22:40:56 BLANKRK
nice !!! :) |
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2013-09-01 12:03:17 abhishek nagpal
what will be the answer for 44? 2 or 3? |
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2013-02-05 00:13:02 Spar!k
sieve just makes it slower. sqrt(n) is ok |
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2012-12-15 22:04:39 Branfili
@Kennard 2, because 36=6*6 |
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2012-02-09 07:58:24 maverick
I am continuously getting Error Wrong problem code! Please fix this error! I think the problem is temporarily removed from the main problemset. |
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2010-12-27 18:20:16 Kennard
36? is the answer is 2 or 4? |