ITERA - The Iteration

Given a code as follows:

      int main()
      {
         int i, j, n, m, nc, count;
         scanf("%d", &nc);
         while (nc--)
         {
           scanf("%d %d", &n, &m);
           count = 0;
           for (i = 0; i < n; i++)
           {
             for (j = 0; j < m; j++)
             {
               count++;
             }
           }
           printf("%d\n", count);
         }
         return 0;
      }

You have to find how many times will the code run for given values of n and m.

Input

Input starts with an integer T (≤ 1000), denoting the number of test cases.

Each case contains two integers n (1 <= n <= 10000) and m (1 <= m <= 10000).

Output

For each case, print the number denoting how many times will the above code run.

The output will fit in a 32-bit integer.

Example

Input:
1
2 1

Output:
Case 1: 2

Added by:Md. Khirul Islam
Date:2013-06-15
Time limit:1s
Source limit:20000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
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hide comments
2023-03-17 21:27:50 Simes
How many times the code will run? It will run once. or are we supposed to output the final values of Count?
But what is the value for NC?
How on earth do people get AC with such a poorly worded problem?
2018-07-06 09:21:28
There is no input. Admins, please hide the problem.
2013-06-15 19:04:58 Robert Gerbicz
Actually the c compiler gives multiple errors for the above code.
2013-06-15 19:04:51 Francky
This is a tutorial problem, and it's not very well formated. Moved.
2013-06-15 19:04:50 ওয়াসী (Wasi)
Can't get why SIGXFSZ?? when there is atmost 1000 cases to print

Last edit: 2013-06-28 09:43:41
2013-06-15 18:14:13 shiva_hellgeek
tutorial problem...
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