JNEXT - Just Next !!!

DevG likes too much fun to do with numbers. Once his friend Arya came and gave him a challenge, he gave DevG an array of digits which is forming a number currently (will be called as given number). DevG was challanged to find the just next greater number which can be formed using digits of given number. Now DevG needs your help to find that just next greater number and win the challenge.

Input

The first line have t number of test cases (1 <= t <= 100). In next 2*t lines for each test case first there is number n (1 <= n <= 1000000) which denotes the number of digits in given number and next line contains n digits of given number separated by space.

Output

Print the just next greater number if possible else print -1 in one line for each test case.

Note : There will be no test case which contains zero in starting digits of any given number.

Example

Input:
2
5
1 5 4 8 3
10
1 4 7 4 5 8 4 1 2 6

Output:
15834
1474584162

Added by:! include(L.ppt)
Date:2012-08-31
Time limit:1.297s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: ASM64
Resource:MNNIT OPC 31-08-2012

hide comments
2019-10-31 10:19:32
@owl_a same here
2019-10-23 21:10:50
In case of sorting......use merge sort in place of quick sort
It suggests my experience after getting a lot of Tle

Last edit: 2019-10-23 21:11:12
2019-10-21 11:22:42
I have used stack with o(n) soln
2019-07-09 16:05:14
How to solve this Problem Using Stack?? : )
2019-07-02 12:45:37
accepted with python 3. Optimize your code
2019-05-23 18:29:32
Print array!! Don't print number Costed 2 WA
2019-05-07 08:22:56
For an editorial, view this :
https://www.youtube.com/watch?v=t_TMt_BFGiQ
2019-05-02 12:24:19
why its TLE even though if we use next_permutation?
2019-04-26 18:43:26
Why am I getting a TLE in linear time solution in Java? I have used Fast I/O too.

Last edit: 2019-04-26 18:44:11
2019-04-25 15:29:56
Is there any way to do it in linear time or using Stack?
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