LCMSUM - LCM Sum

Given n, calculate the sum LCM(1, n) + LCM(2, n) + .. + LCM(n, n), where LCM(i, n) denotes the Least Common Multiple of the integers i and n.

Input

The first line contains T the number of test cases. Each of the next T lines contain an integer n.

Output

Output T lines, one for each test case, containing the required sum.

Example

Sample Input:
3
1
2
5

Sample Output:
1
4
55

Constraints

1 <= T <= 300000
1 <= n <= 1000000


Added by:Varun Jalan
Date:2010-01-24
Time limit:1s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: PERL6
Resource:own problem used for Codechef Snackdown Onsite

hide comments
2023-12-09 10:55:06
Ans wrong. Thử nghiệm vẫn đúng ???


Last edit: 2023-12-09 10:55:31
2023-07-27 12:16:59
If you faced TLE, read about LcmSum formula , it using ETF to caculate
2023-06-20 07:24:40
everyone talk about TLE , but you will waste hours if don't know the formula

Last edit: 2023-06-20 07:33:29
2023-02-05 10:21:52
Does this problem has anything to do with Mobius Inversion ?
2022-08-29 18:41:11
you can check out my method here if you are getting a TLE and cannot figure out why: <snip>
[Simes]: No thanks, we don't want links to solutions.

Last edit: 2022-08-29 19:53:39
2022-06-06 23:53:28
how could you solve this problem guys?
2022-03-27 11:55:04
Just avoid t * sqrt(n)
I'm using generate all factor from prime factor and i get AC. Hope you guys get it
2021-10-21 13:01:05
WA in ALL GO's
2021-07-30 02:22:35 Vladimir Kirichenkoff
To solve this task perform next steps:
1. Fast factor base generation.
2. Find recurrent formula.
2021-06-27 17:13:18
If you are doing this question in O(n log n +t*sqrt(n) ) (TLE will come)
Means you know the concept.
Just to avoid sqrt(n) pre-compute answer just like sieve concept.
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