ACODE  Alphacode
Alice and Bob need to send secret messages to each other and are discussing ways to encode their messages:
Alice: “Let’s just use a very simple code: We’ll assign ‘A’ the code word 1, ‘B’ will be 2, and so on down to ‘Z’ being assigned 26.”
Bob: “That’s a stupid code, Alice. Suppose I send you the word ‘BEAN’ encoded as 25114. You could decode that in many different ways!”
Alice: “Sure you could, but what words would you get? Other than ‘BEAN’, you’d get ‘BEAAD’, ‘YAAD’, ‘YAN’, ‘YKD’ and ‘BEKD’. I think you would be able to figure out the correct decoding. And why would you send me the word ‘BEAN’ anyway?”
Bob: “OK, maybe that’s a bad example, but I bet you that if you got a string of length 5000 there would be tons of different decodings and with that many you would find at least two different ones that would make sense.”
Alice: “How many different decodings?”
Bob: “Jillions!”
For some reason, Alice is still unconvinced by Bob’s argument, so she requires a program that will determine how many decodings there can be for a given string using her code.
Input
Input will consist of multiple input sets. Each set will consist of a single line of at most 5000 digits representing a valid encryption (for example, no line will begin with a 0). There will be no spaces between the digits. An input line of ‘0’ will terminate the input and should not be processed.
Output
For each input set, output the number of possible decodings for the input string. All answers will be within the range of a 64 bit signed integer.
Example
Input: 25114 1111111111 3333333333 0 Output: 6 89 1
hide comments
harshh3010:
20210131 20:18:14
Result for inputs like 10001 will be 0 

iwandepe:
20210124 09:24:30
if you still confuse how to solve this problem. try to think about fibonacci sequence. then handle the case with '0' values 

subhamhimself:
20210111 19:21:14
BINOD 

ritik042:
20210111 15:35:42
BINOD 

vinod_07:
20210101 09:34:25
Nice problem. FYI, all the test cases are valid and there is no possibility of answer being 0. 

destynova:
20201212 09:48:33
Another important test case: 1101 > 1. 

rahat108:
20201203 08:17:28
getting NZEC for java 

coder582:
20201006 20:19:12
a. I used 2D DP


anuragsati7:
20200927 09:19:24
AC in 70 go yess! 

whiterose000:
20200922 08:47:59
Hint : It's easy if you know the famous Fibonacci Sequence :) Last edit: 20200922 08:48:46 
Added by:  Adrian Kuegel 
Date:  20050709 
Time limit:  0.5s 
Source limit:  50000B 
Memory limit:  1536MB 
Cluster:  Cube (Intel G860) 
Languages:  All 
Resource:  ACM East Central North America Regional Programming Contest 2004 