ANARC05B  The Double HeLiX
Two ﬁnite, strictly increasing, integer sequences are given. Any common integer between the two sequences constitute an intersection point. Take for example the following two sequences where intersection points are
printed in bold:
 First= 3 5 7 9 20 25 30 40 55 56 57 60 62
 Second= 1 4 7 11 14 25 44 47 55 57 100
You can ‘walk” over these two sequences in the following way:
 You may start at the beginning of any of the two sequences. Now start moving forward.
 At each intersection point, you have the choice of either continuing with the same sequence you’re currently on, or switching to the other sequence.
The objective is ﬁnding a path that produces the maximum sum of data you walked over. In the above example, the largest possible sum is 450, which is the result of adding 3, 5, 7, 9, 20, 25, 44, 47, 55, 56, 57, 60, and 62
Input
Your program will be tested on a number of test cases. Each test case will be speciﬁed on two separate lines. Each line denotes a sequence and is speciﬁed using the following format:
n v1 v2 ... vn
Where n is the length of the sequence and vi is the ith element in that sequence. Each sequence will have at least one element but no more than 10,000. All elements are between 10,000 and 10,000 (inclusive).
The last line of the input includes a single zero, which is not part of the test cases.
Output
For each test case, write on a separate line, the largest possible sum that can be produced.
Sample
Input: 13 3 5 7 9 20 25 30 40 55 56 57 60 62 11 1 4 7 11 14 25 44 47 55 57 100 4 5 100 1000 1005 3 12 1000 1001 0 Output: 450 2100
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distructo:
20200925 17:13:53
While switching to another array make sure to get the index of that common element in the 2nd array...if you are using dp+binary search 

luismbaezco:
20200910 04:54:43
O(N*log(N)) Using DP (Top Down) + lower_bound (Binary Search), but it takes a long time to think 

mega4411:
20200827 07:44:17
don't think about dp or binary search 

rehank478:
20200805 07:01:18
I think it's greedy problem. 

jopdhiwaala:
20200722 17:48:22
Made a mistake you can have not intersection points as well. 

coolboy7:
20200712 18:03:24
solving it with dp and binary will simply make an easy problem complex 

rum3r:
20200528 11:30:44
Don't waste your time on this problem.. It's not even DP :( 

amar_shukla1:
20200516 19:07:44
just do prefix array method 

shekhar_12345:
20200505 22:48:23
o(n) no binary search no dp 

avik26091998:
20200503 11:04:33
take care of testcases

Added by:  ~!(*(@*!@^& 
Date:  20090705 
Time limit:  1s 
Source limit:  50000B 
Memory limit:  1536MB 
Cluster:  Cube (Intel G860) 
Languages:  All except: ERL JSRHINO NODEJS PERL6 VB.NET 
Resource:  ANARC 2005 