AP2 - AP - Complete The Series (Easy)
Arithmatic and geometric Progressions are 2 of the well known progressions in maths.
Arithmatic progression(AP) is a set in which the difference between 2 numbers in constant. for e.g., 1, 3, 5, 7, 9 .... In this series the difference between 2 numbers is 2.
The task here is very simple indeed.
You will be given the 3rd term , 3rd last term and the sum of the series. You need print length of the series & the series.
First line will contain a number indicating the number of test cases.
Each of the following t lines will have 3 number '3term' ,'3Lastterm' and 'sum'
3term - is the 3rd term in of the series and
3Lastterm - is the 3rd term in of the series and
sum - is the sum of the series.
For each input of the test case, you need to print 2 lines.
First line should have 1 value - the number of terms in the series.
2nd line of the output should print the series numbers separated by single space.
Input: 1 3 8 55 Output: 10 1 2 3 4 5 6 7 8 9 10
- In all the test cases, all the series elements are positive integers.
- The series will have at least 7 elements.
- number of test cases <=100.
- All the numbers will fit in 64 bits (long long in C)
dont forget to take numbers in long long int
python take lots of time
pure high school maths and equations nothing else. very easy question.
@true_saiyan it is written that The series will have at least 7 elements. So there is no chance for both to be equal.
Just one thing you need to know:
is it possible to solve in java? because of time constraint. please advice.
1st term + last term = 2nd term + last 2nd term = 3rd term + last 3rd term
Last edit: 2018-09-29 18:26:28
It's misconception here in statements that n >=7. I'm pretty sure it's >= 6.
What is this