BUNNIES - Bunnies

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Pompom bunny has N strange eggs. The i-th egg is broken by tapping it exactly Ai times. Pompom needs to break K eggs as soon as possible for cooking a rice omelette. However she has been put in an uncomfortable situation. Someone has shuffled the eggs! Pompom knows the values Ai, however she doesn't know which egg is which. She'd like to minimize the worst-case number of taps. What is the minimal number?

Input

The first line contains an integer T, the number of test cases. Then T test cases follow. The first line for each test case has 2 integers N and K. Then next line has N integers A1, A2 ... AN.

Output

For each test case, print the minimal number of taps for the worst-case.

Constraints

1 <= T <= 10

1 <= K <= N <= 3000

1 <= Ai <= 1000000

Example

Input:
3
2 1
5 8
2 1
5 58
3 2
1 2 3

Output:
8
10
5

Explanation

In the first case, if a egg isn't broken after 5 taps, she should continue to tap the same egg.

In the second case, if a egg isn't broken after 5 taps, she should tap another egg 5 times.


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smso: 2020-03-27 19:10:00

1
4 3
101 100 3 2
ans: 101+3+3+2=109

alfa_razra1505: 2017-08-15 10:35:24

whats the output for
1
7 2
1 3 3 3 3 3 1000000

is it 11 or 19 ?

Prashant Khurana: 2014-02-09 12:53:05

@Himanshu, I too think it should be 20, take any 2 eggs. Hit each one of them 10 times. You are bound to break 1 of the egg.

Last edit: 2014-02-09 14:29:37
himanshu jain: 2012-08-27 05:07:30

@Xunie J: why it should be 20? it should be 27 only because in the worst case pompon taps 9 times all the 3 eggs and which will result in 1 egg broken.

chetan: 2012-07-29 11:18:59

can you please check my solution id, I believe it covers all possible cases but is still showing WA...the id is 7389887

Last edit: 2012-07-29 18:31:29
devu: 2012-07-29 10:57:38

@Chetan Dalal : Rethink Your Logic with Proof of Correctness..you will surey get it correct.

Last edit: 2013-01-17 10:01:07
Xunie J: 2012-03-15 13:02:50

I think the answer for
3 1
100 10 9 should be 20
but some accepted source code output 27...

Alex Anderson: 2012-02-11 03:38:02

This one was pretty fun. Nice problem

Fernando Fonseca [ITA]: 2012-02-09 13:59:31

For that case, Pompom can tap all eggs 1 time, breaking both 1 eggs, then tap the remaining 4 one time each, breaking the 2 eggs. This gives a total of only 10 taps on the worst case.

Last edit: 2012-02-09 14:00:24
Devil D: 2012-02-09 12:18:55

whats the output for
6 4
1 2 1 2 11 5

Is it 20?


Added by:Paulo Costa
Date:2012-02-01
Time limit:1s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: ASM64
Resource:PUCP