BYTESM2  Philosophers Stone
One of the secret chambers in Hogwarts is full of philosopher’s stones. The floor of the chamber is covered by h × w square tiles, where there are h rows of tiles from front (first row) to back (last row) and w columns of tiles from left to right. Each tile has 1 to 100 stones on it. Harry has to grab as many philosopher’s stones as possible, subject to the following restrictions:
 He starts by choosing any tile in the first row, and collects the philosopher’s stones on that tile. Then, he moves to a tile in the next row, collects the philosopher’s stones on the tile, and so on until he reaches the last row.
 When he moves from one tile to a tile in the next row, he can only move to the tile just below it or diagonally to the left or right.
Input
The first line consists of a single integer T, the number of test cases. In each of the test cases, the first line has two integers. The first integer h (1 <= h <= 100) is the number of rows of tiles on the floor. The second integer w (1 <= w <= 100) is the number of columns of tiles on the floor. Next, there are h lines of inputs. The ith line of these, specifies the number of philosopher’s stones in each tile of the ith row from the front. Each line has w integers, where each integer m (0 <= m <= 100) is the number of philosopher’s stones on that tile. The integers are separated by a space character.
Output
The output should consist of T lines, (1 <= T <= 100), one for each test case. Each line consists of a single integer, which is the maximum possible number of philosopher’s stones Harry can grab, in one single trip from the first row to the last row for the corresponding test case.
Example
Input: 1 6 5 3 1 7 4 2 2 1 3 1 1 1 2 2 1 8 2 2 1 5 3 2 1 4 4 4 5 2 7 5 1 Output: 32 //7+1+8+5+4+7=32
hide comments
Darren Sun:
20140720 11:21:04
The actual test cases do not ensure w integers in each line. This creates unnecessary troubles for problem solvers using languages like Java. 

Ravichandra Enaganti:
20140715 10:53:40
Until solving this problem, I was afraid of DP. This gave me a confidence that I can solve a DP problem. 

The Exorcist:
20140715 08:06:52
recursion + memoization == TLE ...?? 

Baojun Wang:
20140627 21:14:59
not O(3*n)? got TLE 

Shailendra Kumar:
20140605 21:28:00
my First DP!! nd now i luv DP :P 

JordanBelfort:
20140604 21:09:35
too easy :) 

Pranav Maneriker:
20140518 10:45:07
Why is c++ not allowed?


SHIVAM DIXIT:
20140423 20:46:10
Last edit: 20140423 20:46:38 

SHIVAM DIXIT:
20140423 20:46:10
simple dp...same as miserman 

Satinjal Yadav:
20140419 21:01:33
easy dp!, although my first one... 
Added by:  Paritosh Aggarwal 
Date:  20090221 
Time limit:  1s 
Source limit:  50000B 
Memory limit:  1536MB 
Cluster:  Cube (Intel G860) 
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