CANTON - Count on Cantor

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One of the famous proofs of modern mathematics is Georg Cantor's demonstration that the set of rational numbers is enumerable. The proof works by using an explicit enumeration of rational numbers as shown in the diagram below.

1/1 1/2 1/3 1/4 1/5 ...
2/1 2/2 2/3 2/4
3/1 3/2 3/3
4/1 4/2
5/1

In the above diagram, the first term is 1/1, the second term is 1/2, the third term is 2/1, the fourth term is 3/1, the fifth term is 2/2, and so on.

Input

The input starts with a line containing a single integer t <= 20, the number of test cases. t test cases follow.

Then, it contains a single number per line.

Output

You are to write a program that will read a list of numbers in the range from 1 to 10^7 and will print for each number the corresponding term in Cantor's enumeration as given below.

Example

Input:
3
3
14
7

Output:
TERM 3 IS 2/1
TERM 14 IS 2/4
TERM 7 IS 1/4

hide comments
cypher33: 2018-12-27 06:15:56

@abhinav__ your comment made my day lmao

adipat: 2018-10-12 19:55:37

This was how I solved it. First identify the diagonal pattern. A diagonal k has k terms and the total terms upto that diagonal will be (1+2+...+k). Using this property, locate the diagonal in which n will lie. From there the exact row and column of the nth term can be found by iterating through the diagonal up or down depending on whether it's an odd or even diagonal.

rajat_enzyme: 2018-08-20 19:58:32

Last edit: 2018-08-20 20:01:19
quannguyenlhp: 2018-08-18 06:27:54

AC in 1000000th go, 5 sec

Last edit: 2018-08-18 06:28:15
harsh771: 2018-07-08 19:02:48

Easy to solve once you observe the pattern!

vritta: 2018-06-18 13:16:25

1/1 1/2 1/3 1/4 1/5 ...
2/1 2/2 2/3 2/4
3/1 3/2 3/3
4/1 4/2
5/1
observe pattern by drawing arrow between values of corresponding terms. Rest is easy.Or visit http://en.wikipedia.org/wiki/File:Diagonal_argument.svg for more clear explanation.

Last edit: 2018-06-18 13:18:42
itachi_2016: 2018-06-12 10:57:50

Last edit: 2018-06-12 10:59:06
codesniper99: 2018-04-26 15:53:47

the sniper leaves his regards :3

abhinav__: 2018-04-02 11:03:39

chutiyo itna aasan sawal tha AC in 1 go likh ke khush kya ho rahe ho.

lefthander: 2018-03-31 06:37:21

AC in 1 GO by Binary Search :v 0.0 sec

Last edit: 2018-03-31 06:38:06

Added by:Thanh-Vy Hua
Date:2005-02-27
Time limit:5s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: NODEJS PERL6 VB.NET
Resource: ACM South Eastern European Region 2004