## CEQU - Crucial Equation

Let us see the following equation,

ax+by=c

Given three positive integers a, b and c. You have to determine whether there exists at least one solution for some integers value of x and y where x, y may be negative or non-negative integers.

For example if a=2, b=4 and c=8 then the equation will be 2x+4y=8, and hence, for x=2 and y=1, there exists a solution.

Let us see another example for a=3, b=6 and c=7, so the equation will become 3x+6y=7 and there exists no solution satisfying this equation.

Input

Input starts with an integer T (1<=T<=105) denoting the number of test cases. Each test case contains three integers a, b, and c. (1<=a, b, c<=106).

Output

For each test case of input print the case number and “Yes” if there exists at least one solution, print “No” otherwise.

 Sample Input Output for Sample Input 2 2 4 83 6 7 Case 1: Yes Case 2: No

Problem Setter: Md Abdul Alim, CEO and Founder at CodeMask

 < Previous 1 2 3 4 5 6 7 8 Next > Narendra pal: 2015-05-31 11:53:19 can zero be the value of x or y ?? Naman Goyal: 2015-05-20 21:31:01 Good one, I went in completely wrong direction with prime factorizing a,b and c and wasted quite a lot time. Bozidar: 2015-04-22 19:04:00 Don't forget to put space betwen ':' and 'Yes' or 'No' . Costed me a hell of nervs.... Dhruv k14: 2015-03-07 20:43:56 and the printing errors cause multiple WAs for the infiniteth time Indian Cyber Army (IndiShell): 2015-02-03 17:57:46 My 30th :) Feeling motivated !! :D Gaurav sharma: 2015-01-30 18:49:20 go green...:P :) before this try ENIGMATH