## CMPLS - Complete the Sequence!

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You probably know those quizzes in Sunday magazines: given the sequence 1, 2, 3, 4, 5, what is the next number? Sometimes it is very easy to answer, sometimes it could be pretty hard. Because these "sequence problems" are very popular, ACM wants to implement them into the "Free Time" section of their new WAP portal.

ACM programmers have noticed that some of the quizzes can be solved by describing the sequence by polynomials. For example, the sequence 1, 2, 3, 4, 5 can be easily understood as a trivial polynomial. The next number is 6. But even more complex sequences, like 1, 2, 4, 7, 11, can be described by a polynomial. In this case, 1/2.n2-1/2.n+1 can be used. Note that even if the members of the sequence are integers, polynomial coefficients may be any real numbers.

Polynomial is an expression in the following form:

If aD <> 0, the number D is called a degree of the polynomial. Note that constant function P(n) = C can be considered as polynomial of degree 0, and the zero function P(n) = 0 is usually defined to have degree -1.

### Input

There is a single positive integer T on the first line of input (equal to about 5000). It stands for the number of test cases to follow. Each test case consists of two lines. First line of each test case contains two integer numbers S and C separated by a single space, 1 <= S < 100, 1 <= C < 100, (S+C) <= 100. The first number, S, stands for the length of the given sequence, the second number, C is the amount of numbers you are to find to complete the sequence.

The second line of each test case contains S integer numbers X1, X2, ... XS separated by a space. These numbers form the given sequence. The sequence can always be described by a polynomial P(n) such that for every i, Xi = P(i). Among these polynomials, we can find the polynomial Pmin with the lowest possible degree. This polynomial should be used for completing the sequence.

### Output

For every test case, your program must print a single line containing C integer numbers, separated by a space. These numbers are the values completing the sequence according to the polynomial of the lowest possible degree. In other words, you are to print values Pmin(S+1), Pmin(S+2), .... Pmin(S+C).

It is guaranteed that the results Pmin(S+i) will be non-negative and will fit into the standard integer type.

### Example

Sample Input:

```4
6 3
1 2 3 4 5 6
8 2
1 2 4 7 11 16 22 29
10 2
1 1 1 1 1 1 1 1 1 2
1 10
3

```

Sample Output:

```7 8 9
37 46
11 56
3 3 3 3 3 3 3 3 3 3
```
Warning: large Input/Output data, be careful with certain languages

 < Previous 1 2 3 4 5 6 Next > Anand: 2015-06-28 20:09:10 It is lagrange's interpolation problem. I've implemented the formula correctly. passes all the testcases still wa. any suggestions ? srishty: 2015-06-25 19:13:47 my solution is working fine at ideone,but here its WA cant figure out the problem.any suggestions please! srishty: 2015-06-24 16:52:40 could you explain the third output please! Mohita Gakhar: 2015-06-16 20:17:10 My code is working fine on Ideone. But here it is giving WA. Any Suggestions. candide: 2015-06-07 00:35:09 @dj01 The two lines 1 10 3 mean the sequence is limited to the single element 3. Of course, the polynomial P with minimal degree such that P(1)=3 is the constant polynomial P=3. So corresponding output is: 3 3 3 3 3 3 3 3 3 3 dj01: 2015-05-31 15:23:13 cant understand the third input....how is that a sequence? Syaorann: 2015-04-09 15:26:03 @nagendra, yes it is a polynomia of degree >1, but the variable n is given, and An is needed to comput. so its a matrix about A*n=P, what we need to do is just get the 1 degree solution A, and compute the reasult S+1..S+C, am i wrong? nagendra gupta: 2015-04-02 18:24:19 @syaorann Its clearly mentioned in the question that equation is a polynomia of degree > 1 how come you think of linear algebra. Syaorann: 2015-03-18 12:58:28 so its a linear algebra Problem about solve Matrix?