COMDIV - Number of common divisors
You will be given T (T<=10^6) pair of numbers. All you have to tell is the number of common divisors between two numbers in each pair.
Input
First line of input: T (Number of test cases)
In next T lines, each have one pair A B (0 < A, B <= 10^6)
Output
One integer describing number of common divisors between two numbers.
Example
Input: 3
100000 100000
12 24
747794 238336
Output: 36
6
2
hide comments
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srjsunny:
2018-02-20 20:36:06
use scanf and printf , no need to use seive |
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viniet_sw:
2018-01-02 15:14:00
bhosadi waalo ac in one go ka kya show off krte rehte ho gand utha ke har jagah |
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sanyam19:
2018-01-02 14:48:23
AC in 1 go :) |
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karthik1997:
2017-12-27 16:39:58
Man , Never thought i would end up with fastest submission till date ( 0.10s )
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chetan4060:
2017-12-19 18:25:20
use sieve first then gcd
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sirjan13:
2017-11-02 21:22:19
50th =)
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madhur4127:
2017-10-04 15:04:19
If TLE: use || ios::sync_with_stdio(0); cin.tie(0); || in C++ to make I/O fast.
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naveen_4199:
2017-09-27 17:42:22
use scanf and printf to resolve TLE error along with better mathematical logic |
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prabodh prakash:
2017-05-03 21:51:19
cout, cin gave me few TLE and then god knows what gave me WA - finally correct ! |
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aditya9125:
2017-03-21 16:19:01
Using cin,cout along with fast ip/op passed in every problem I have solved so far,so never used scanf,printf in a C++ code, but here I don't know why using scanf,printf becomes a compulsion.This thing annoys me a lot.If anyone can help,pls help me know that what's the use of "ios_base::sync_with_stdio(false); cin.tie(NULL) in a c++ code" if we always have to use scanf,printf Last edit: 2017-03-21 16:19:59 |
| Added by: | Mir Wasi Ahmed |
| Date: | 2010-10-31 |
| Time limit: | 0.600s |
| Source limit: | 50000B |
| Memory limit: | 1536MB |
| Cluster: | Cube (Intel G860) |
| Languages: | All except: ASM64 |
| Resource: | Own problem, used in UODA TST |
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