CPTTRN1 - Character Patterns (Act 1)


Using two characters: . (dot) and * (asterisk) print a chessboard-like pattern. The first character printed should be * (asterisk).

Input

You are given t < 100 - the number of test cases and for each of the test cases two positive integers: l - the number of lines and c - the number of columns in the pattern (l, c < 100).

Output

For each of the test cases output the requested pattern (please have a look at the example). Use one line break in between successive patterns.

Example

Input:
3
3 1
4 4
2 5

Output:
*
.
*

*.*.
.*.*
*.*.
.*.*

*.*.*
.*.*.

hide comments
thesyncoder: 2018-06-10 07:52:28

easy enough , just do three nested loops , one outer loop for your array or vector , and the inner ones j and k for simple matrix like loops, and print * if j+k %2 ==0 else print .Happy coding.

somyadeep99: 2018-06-01 11:54:46

i have got ac in one go, if you want solution send request mail at somyadeep99@gmail.com
just think about odd even logic.

vicc255: 2018-03-17 19:12:09

I thought the question was wrong but it's correct.See odd and even similarity between row no. and column no.
Good luck.

jairaj_sahgal: 2018-03-10 15:18:23

I love it

secret_santa1: 2017-12-20 15:57:16

Approach-1)Draw a chessboard and enter the given values i.e. fill the chessboard with "." and "*"(say 4*4 chessboard)
2)Observe the position of all the asterisk (or dots) and figure out the pattern.
3)Hint: Odd/even positions.
Note-All given input & output are correct.

vinay11vishu: 2017-11-13 20:08:34

@vshantam
I am able to get the pattern correctly, but with my own input. Logic seems to be right but i am missing something with their inputs. Can you mail me your solution at karmavinayvkv@gmail.com.. Would be great help..

vshantam: 2017-11-12 10:40:24

@vinay11vishu
The idea i implemented was to run two for loops and when (i %2==0 and j%2==0) or (i%2!=0 and j%2!=0) then print '*' or else print '.' where i and j depends on input on each line . works for me perfectly .

Last edit: 2017-11-12 10:42:33
vinay11vishu: 2017-10-29 11:17:16

Can anybody explain me how the input should be given to this program ??

Last edit: 2017-10-29 12:35:27
imtiaz_mehedi: 2017-08-30 19:35:31

i have done it..it shows the right output but here it said it's wrong

Last edit: 2017-08-30 19:35:57
deepk_keshri: 2017-08-21 19:48:42

if line no. is odd,odd position have * and if line is even ,even position will '*'


Added by:kuszi
Date:2012-09-03
Time limit:0.25s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: ASM64