CUBEFR - Cube Free Numbers


A cube free number is a number who’s none of the divisor is a cube number (A cube number is a cube of a integer like 8 (2 * 2 * 2) , 27 (3 * 3 * 3) ). So cube free numbers are 1, 2, 3, 4, 5, 6, 7, 9, 10, 11, 12, 13, 14, 15, 17, 18 etc (we will consider 1 as cube free). 8, 16, 24, 27, 32 etc are not cube free number. So the position of 1 among the cube free numbers is 1, position of 2 is 2, 3 is 3 and position of 10 is 9. Given a positive number you have to say if its a cube free number and if yes then tell its position among cube free numbers.

Input

First line of the test case will be the number of test case T (1 <= T <= 100000) . Then T lines follows. On each line you will find a integer number n (1 <= n <= 1000000).

Output

For each input line, print a line containing “Case I: ”, where I is the test case number. Then if it is not a cube free number then print “Not Cube Free”. Otherwise print its position among the cube free numbers.

Example

Sample Input:
10
1
2
3
4
5
6
7
8
9
10

Sample Output:
Case 1: 1
Case 2: 2
Case 3: 3
Case 4: 4
Case 5: 5
Case 6: 6
Case 7: 7
Case 8: Not Cube Free
Case 9: 8
Case 10: 9

hide comments
kira28: 2016-12-28 13:23:52

another sieve ques :/

madhavgaba: 2016-12-24 05:24:35

modify sieve and precompute......AC in third go;)

surajmall: 2016-10-23 11:13:20

seieve and some smart work needed

kmrrv: 2016-09-15 19:20:27

beware of output format

karan_batra: 2016-08-28 11:13:57

AC in one go :D. Simple modification of sieve.

agralalarocks: 2016-07-26 22:49:19

Could someone please take a look at my code its VAKNIg on ideone

hmp: 2016-07-05 03:08:52

why same code giving compilation error with C++14 and AC with C++4.3.2

praval_singhal: 2016-06-03 20:55:44

First the very first Time used lower_bound. Got AC :)

Subhendu Sethi: 2016-05-21 03:04:32

No need to Prime Factorize. Think about sieving! Easy.

mohitgupta07: 2016-05-13 22:36:02

dun knw why getting wrong answer -_- can anyone tell me dat how many cube free no.s lie in this range!!


Added by:Muhammad Ridowan
Date:2011-06-14
Time limit:0.100s-1s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: ASM64
Resource:Own. For alternate thanks Sayef Azad Sakin