EIGHTS  Triple Fat Ladies
Pattern Matchers have been designed for various sorts of patterns. Mr. HKP likes to observe patterns in numbers. After completing his extensive research on the squares of numbers, he has moved on to cubes. Now he wants to know all numbers whose cube ends in 888.
Given a number k, help Mr. HKP find the k^{th} number (indexed from 1) whose cube ends in 888.
Input
The first line of the input contains an integer t, the number of test cases. t test cases follow.
Each test case consists of a single line containing a single integer k (1 <= k <= 2000000000000).
Output
For each test case, output a single integer which denotes the k^{th} number whose cube ends in 888. The result will be less than 2^{63}.
Example
Input: 1 1 Output: 192
hide comments
amitnsky:
20180816 11:04:24
reason behind AP is that we need some number after adding that last three digits should not disturbed of 192^3.


bansalabhi_98:
20180627 09:00:44
@sreejoy4242 why separate case for k==1


bansalabhi_98:
20180627 08:55:31
getting wrong answer using simple maths


jeet9:
20180609 19:30:53
The test case may be long. Last edit: 20180609 19:31:32 

wrzoboo:
20180604 14:21:39
first run a bruteforce program to print you the first few elements of the sequence (using string manipulation). notice pattern, get ac in 7 lines (or less) 

davisk83:
20180531 11:21:42
test 

iamnotsanju:
20180406 20:57:47
can anyone tell me how to figure out that the numbers will be in AP?.


jmr99:
20180311 11:21:18
@sreejoy4242


riyadhrazzaq:
20180309 15:07:54
There should be another test case.


vikashumain:
20180306 11:57:34
Total time waste 
Added by:  Matthew Reeder 
Date:  20061030 
Time limit:  1.197s 
Source limit:  30000B 
Memory limit:  1536MB 
Cluster:  Cube (Intel G860) 
Languages:  All except: ERL JSRHINO NODEJS PERL6 VB.NET 
Resource:  AlKhawarizm 2006 