EIGHTS  Triple Fat Ladies
Pattern Matchers have been designed for various sorts of patterns. Mr. HKP likes to observe patterns in numbers. After completing his extensive research on the squares of numbers, he has moved on to cubes. Now he wants to know all numbers whose cube ends in 888.
Given a number k, help Mr. HKP find the k^{th} number (indexed from 1) whose cube ends in 888.
Input
The first line of the input contains an integer t, the number of test cases. t test cases follow.
Each test case consists of a single line containing a single integer k (1 <= k <= 2000000000000).
Output
For each test case, output a single integer which denotes the k^{th} number whose cube ends in 888. The result will be less than 2^{63}.
Example
Input: 1 1 Output: 192
hide comments
milind_jarvis:
20180123 13:41:18
Total time waste _ 

srjsunny:
20180117 14:41:30
its simple, number of the this form 10(19+25(k1))+2. you can deduce this if you see the example carefully 

venkat016:
20180111 17:06:02
Use Spoj Toolkit thanks to @ajayc1007 and @prasad_235 

harshit_99:
20171229 07:19:27
Nobody asks you to write AC in one go bitches..!!


anushka_ahuja:
20171225 05:50:12
Last edit: 20171225 05:51:35 

skaptox:
20171222 22:50:24
Shut up, anybody wants know your solutions! Last edit: 20171222 22:50:51 

akhand_mishra:
20171219 15:04:10
look for using AP(ARITHMATIC PROGRESSION) in the problem. 

dsri_99:
20171218 14:16:39
AC in one go..........


saurabhsunil95:
20171206 19:38:31
AC in one go 

true_saiyan:
20171114 07:37:16
1 line of code in python 
Added by:  Matthew Reeder 
Date:  20061030 
Time limit:  1.197s 
Source limit:  30000B 
Memory limit:  1536MB 
Cluster:  Cube (Intel G860) 
Languages:  All except: ERL JSRHINO NODEJS PERL6 VB.NET 
Resource:  AlKhawarizm 2006 