Given the value of N, you will have to find the value of G. The meaning of G is given in the following code

G = 0;
for (i = 1; i < N; i++)
  for (j = i+1; j <= N; j++) 
    G += gcd(i, j);

Here gcd() is a function that finds the greatest common divisor of the two input numbers.

Input

The input file contains at most 20000 lines of inputs. Each line contains an integer N (1 < N < 1000001). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero.

Output

For each line of input produce one line of output. This line contains the value of G for the corresponding N. The value of G will fit in a 64-bit signed integer.

Example

Input:
10
100
200000
0

Output:
67
13015
143295493160

Time limit has been changed. Some AC solutions get TLE

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	sunny_saraff: 2020-07-09 12:24:14 Time limit is too strict although AC in 2 GO!! precalculate all divisors of numbers upto given range
	fairooj_04: 2020-04-25 11:47:19 I used euler Totient function.....and getting runtime (SIGSEV) , can anyone help me here?
	zakir_1999: 2020-02-04 12:27:41 Last edit: 2020-02-04 18:52:09
	mushfiq4513: 2019-05-12 16:21:48 modified sieve and totient function..... AC :)
	DK...: 2019-03-16 15:13:43 Try to compute everything into arrays, using vector's push_back function makes TL
	whyamievenhere: 2018-12-19 20:02:17 TLE is killing me here... time limit is really ridiculous,
	badboy_1496: 2018-07-17 06:08:56 hurray!!!! ac in one go...nice way of using sieves
	excel_blaze: 2018-05-21 16:07:54 simple logic and implementation(^_^) nice for beginners Last edit: 2018-05-21 16:08:46
	nadstratosfer: 2018-03-21 19:09:52 Took me 7+ hours in 3 sittings to fit within this retarded TL in PyPy. Props to julkas for showing it's possible.
	anupamwadhwa: 2018-02-07 19:30:21 Try NTG after this one.