INVCNT - Inversion Count


Let A[0...n - 1] be an array of n distinct positive integers. If i < j and A[i] > A[j] then the pair (i, j) is called an inversion of A. Given n and an array A your task is to find the number of inversions of A.

Input

The first line contains t, the number of testcases followed by a blank space. Each of the t tests start with a number n (n <= 200000). Then n + 1 lines follow. In the ith line a number A[i - 1] is given (A[i - 1] <= 10^7). The (n + 1)th line is a blank space.

Output

For every test output one line giving the number of inversions of A.

Example

Input:
2

3
3
1
2

5
2
3
8
6
1


Output:
2
5

hide comments
prodipdatta7: 2017-06-12 18:05:30

AC in one go!!
Only Merge Sort..

abdrakhman: 2017-06-02 09:48:56

AC in one go))))

anurag44: 2017-05-25 04:38:39

Core concept of sorting algorithm..

thefriction: 2017-05-02 14:53:24

thanks @fane_faiz :)

akt_1998: 2017-04-10 19:42:03

Merge Sort->"ACIN1GO"

babur: 2017-04-05 20:10:49

Segment Tree+Merge Sort AC in 1 go :)

the_novice96: 2017-04-05 14:12:46

If BST implementation gets AC, then the test cases are weak because the running time for BST is O(nh), which is O(n^2) in worst case. Basically it should fail if the sequence is sorted.

amandal799: 2017-03-23 18:42:59

solved using binary search tree..AC in one go

rohit9934: 2017-03-15 16:36:06

For Those who are looking for hints.
Well Fenwick tree has a property of counting inversions in an array. Did a lot of work improving time complexity.Great problem. You just have to take care of duplicate elements.AC

jeelapamy: 2017-03-09 10:39:55

ha ha long long


Added by:Paranoid Android
Date:2010-03-06
Time limit:3.599s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: PERL6