INVCNT - Inversion Count


Let A[0...n - 1] be an array of n distinct positive integers. If i < j and A[i] > A[j] then the pair (i, j) is called an inversion of A. Given n and an array A your task is to find the number of inversions of A.

Input

The first line contains t, the number of testcases followed by a blank space. Each of the t tests start with a number n (n <= 200000). Then n + 1 lines follow. In the ith line a number A[i - 1] is given (A[i - 1] <= 10^7). The (n + 1)th line is a blank space.

Output

For every test output one line giving the number of inversions of A.

Example

Input:
2

3
3
1
2

5
2
3
8
6
1


Output:
2
5

hide comments
maaz: 2013-04-15 16:21:46

Take long long int for the no. of inversions .
Cost me many wrong answers.
hint: merge sort

N Hari Prasad: 2013-04-15 16:21:46

try to use printf instead of cout. . got ACC by just changing that. .

Santiago Palacio: 2013-04-15 16:21:46

@saurabh input and output are separated for the machine (even if they are shown at the same time in the console)

Saurabh Jain: 2013-04-15 16:21:46

can we print the output of each test case just after we have input the numbers after n and then leave a blank line and read the input for the next text case?

cannot_in2_coding: 2013-04-15 16:21:46

Last edit: 2011-12-29 23:28:00
Chandan Giri: 2013-04-15 16:21:46

@competer thanks :) i was stuck with that

e@spoj: 2013-04-15 16:21:46

@competer +1

naive_coder: 2013-04-15 16:21:46

please have a look at the range that count will have to store
:)got AC after i just fixed it

Last edit: 2011-08-23 14:15:40
Dunno: 2013-04-15 16:21:46

sometimes it happens.

coder: 2013-04-15 16:21:46

well well, my soln gets accepted in 0k.. lolz.. cant understand the logic how spoj calculates memory consumed. :P


Added by:Paranoid Android
Date:2010-03-06
Time limit:3.599s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: PERL6