MKEQUAL - Make them equal !

You have an array containing N elements. At any move, you choose two indices i and j ( 0 <= i, j < N and i != j ) and increment value at one index and decrement value at other index. You can make this move any number of times. What is the maximum number of elements which can have the same value (after any number of moves) ?


First line consists of T, the number of test cases. (1 <= T <= 100)

T sets follow. Each set contains N, the number of elements in the array, in the first line. (1 <= N <= 100000)

Next line of each set consists of N space separated integers (0 <= value <= 100000)


Output T lines each containing the required answer.


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vaibhav18_: 2019-06-21 11:10:20

just open the spoj toolkit try different cases even if u dont see the question u can do the answer

ankkt16: 2019-01-29 05:39:31

what to print in the case when none of the elements could be made to same no

malcolm123_ssj: 2019-01-25 07:48:13

consider only 2 cases: when sum is divisible by n and when not divisible by n

wrzoboo: 2018-06-05 18:10:57

Really easy one, there are only two options to consider. (Hint: think with zeroes ;) )

sinersnvrsleep: 2018-04-05 15:35:05

no need of binary search just simple adhoc

ameyanator: 2018-03-27 15:37:06

At first I thought we'd have to use some pre defined property but then nah just read the question carefully

nikhil2504: 2017-07-30 15:59:30

Only Pen and Paper can help you !

ankit1cool: 2017-06-06 08:49:00

Good Implementation of binary search

be1048716: 2017-05-19 20:17:53

No getting the question. Can anybody plz explain me the output?

Last edit: 2017-05-19 20:18:24
ashishranjan28: 2017-05-18 07:02:10

very easy

Added by:Pandian
Time limit:0.5s-1s
Source limit:50000B
Memory limit:1536MB
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