PRIME1 - Prime Generator

Peter wants to generate some prime numbers for his cryptosystem. Help him! Your task is to generate all prime numbers between two given numbers!


The input begins with the number t of test cases in a single line (t<=10). In each of the next t lines there are two numbers m and n (1 <= m <= n <= 1000000000, n-m<=100000) separated by a space.


For every test case print all prime numbers p such that m <= p <= n, one number per line, test cases separated by an empty line.


1 10
3 5


Warning: large Input/Output data, be careful with certain languages (though most should be OK if the algorithm is well designed)


After cluster change, please consider PRINT as a more challenging problem.

hide comments
bellapukonda: 2017-07-27 21:19:52

TLE pls tell me the best way for it ->python

karthik_77: 2017-07-24 11:54:46

I am getting a time-exceeded error. How should I go about it?

rambosek: 2017-07-23 14:38:20 -> Python code
Can someone explain me why it doesn't work? (TLE)
There are any other faster solutions to check if number is prime?

Thanks for help ;)

Last edit: 2017-07-23 14:41:23
shreyansh96: 2017-07-18 18:19:14

Why am i getting SIGSEV?

jangir_1: 2017-07-18 17:22:01

Last edit: 2017-07-25 13:55:28
skyzhi: 2017-07-16 07:19:43

AC in 0.00sec happy ?

win2009: 2017-07-16 04:01:12

Proof of my theory above/below: look at jhaanuj2108's code. It is terrible, but it uses a square root trick. He succeeded. almost NO optimizations and he still passed. Use the square root trick.

Last edit: 2017-07-16 04:15:36
win2009: 2017-07-16 03:59:17

The trick is to use the square root trick when considering factors. Sieve or no sieve does not matter. Just use the square root trick and you will be fine. Also, optimize your code. You do not have to handle the worst case scenario ( 999900000 1000000000), at least that was the case for me.

jhaanuj2108: 2017-07-15 23:00:34

import java.util.Scanner;
class PrimeGenerator {
public static boolean isPrime(int no)
return false;
int y=(int) Math.sqrt(no);
for(int j=2;j<=y;j++)
return false;
return true;
public static void main(String[] args) {
Scanner sc=new Scanner(;
int t=sc.nextInt();
for(int i=0;i<t;i++)
int beg=sc.nextInt();
int end=sc.nextInt();
for(int j=beg;j<=end;j++)


pyrojathon: 2017-07-14 12:09:31

Last edit: 2017-07-14 12:18:27

Added by:Adam Dzedzej
Time limit:6s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: NODEJS PERL6