QUADAREA - Maximal Quadrilateral Area

no tags 

You are trying to build a house, but unfortunately you currently have only four available walls with side lengths a, b, c, and d. You want your house to be as big as possible, so you would like to know the largest possible area of any quadrilateral you can construct with these four side lengths.

Input

The first line contains the integer T (1 ≤ T ≤ 2,000), the number of tests. Each test contains a single line with four real numbers: a, b, c, and d (0 < a, b, c, d < 1,000). Note that it will always be possible to form a valid quadrilateral with these lengths; that is, the sum of any three side lengths will be strictly larger than the other one.

Output

For each test case, print a single line containing the largest possible area. Your output will be accepted if it is within 0.01 of the official answer.

Example

Input:
2
1 2 1 2
0.5 0.5 0.5 0.5

Output:
2.00
0.25

For the first test case, it is optimal to construct a rectangle, and for the second, a square is optimal.


hide comments
piyush11696: 2017-08-11 15:43:22

why wa if i use float

sagnik_66: 2017-05-21 11:17:04

Use double and print up to two decimals

prabodh prakash: 2017-05-09 19:08:28

using float gave me a WA. used double to get AC.

nilabja16180: 2017-03-01 12:26:27

Brahmagupta's formlua! AC in one GO!

cake_is_a_lie: 2017-02-14 16:21:20

So using double in c++ I get WA if I just print the results and AC if I print the results truncated to two decimals of precision. Flaky tests => thumbs down.

scorpion_ajay: 2017-02-12 18:47:55

brahmagupta's formula, similar to heros formula...
float-----> WA
double ----> AC
dont know why!

hits_812: 2017-02-07 12:26:21

C users: use double instead of float. cost me 2 WA

esshuvo: 2017-01-03 18:41:36

Formula based problem! Why we assume it as a cyclic quadrilateral area?Problem statement didn't tell that.Can anyone else explain this?

abhi_upadhyay: 2016-12-20 08:52:09

There was a problem when a,b,c,d were float instead of double in c++.Why?

srnsh: 2016-10-27 10:21:54

Java Scanner - 0.42
BufferedReader - 0.31
String Tokenizer - 0.24
Defined Fast I/O - 0.26


Added by:Neal Wu
Date:2008-05-24
Time limit:1s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: ERL JS-RHINO