RAONE - Ra-One Numbers
In the War between good and evil . Ra-One is on the evil side and G-One on the good side.
Ra-One is fond of destroying cities and its G-one's duty to protect them..
Ra-One loves to destroy cities whose Zip Code has special properties. He says he loves to destroy cities which have Ra-One numbers as their ZIp Code.
Any number is Ra-one if the Difference between Sum of digits at even location and Sum of digits at odd location is One (1).. For eg... for 234563 is Ra-One number
digits at odd location are 3,5,3 (unit place is location 1 )
digits at even location are 2,4,6
Diff = (2+4+6)-(3+5+3)=12-11 = 1.
And 123456 is not Ra-One number
diff = (5+3+1) - (2+4+6) = -4
G-One knows this about Ra-one and wants to deploy his Army members in those cities. 1 army member will be deployed in each city.
G-one knows the range of ZIP-Codes where Ra-One might attack & needs your help to find out how many army members he needs.
Can you help Him ?
first line will have only one integer 't' number of Zip-Code ranges. it is followed by t lines
each line from 2nd line cotains 2 integer 'from' and 'to'. these indicate the range of Zip codes where Ra-one might attack .(from and to are included in the range)
A single number for each test case telling how many army members G-One needs to deploy.
each number should be on separate lines
for 1st test case the only number is 10
for 2nd test case numbers are 10,21,32,43,54,65,76,87,98
NOTE: t will be less than 100
from and to will be between 0 and 10^8 inclusive
Indexing starting from 1, from right to left.
Indexing from right to left, don't use long long (getting tle) !! Nice digit dp problem
ac in two goLast edit: 2020-06-03 20:26:32
Worst problem statement . Why didnt they mention order of indexing ?
My 2nd digit dp problem
Manish Kumar Prajapati:
(5+3+1) - (2+4+6) = -3 .
3rd digit dp problem AC in one go
Stupid problem statement...