RENT - Rent your airplane and make money
"ABEAS Corp." is a very small company that owns a single airplane. The customers of ABEAS Corp are large airline companies which rent the airplane to accommodate occasional overcapacity.
Customers send renting orders that consist of a time interval and a price that the customer is ready to pay for renting the airplane during the given time period. Orders of all the customers are known in advance. Of course, not all orders can be accommodated and some orders have to be declined. Eugene LAWLER, the Chief Scientific Officer of ABEAS Corp would like to maximize the profit of the company.
You are requested to compute an optimal solution.
Consider for instance the case where the company has 4 orders:
- Order 1 (start time 0, duration 5, price 10)
- Order 2 (start time 3, duration 7, price 8)
- Order 3 (start time 5, duration 9, price 7)
- Order 4 (start time 6, duration 9, price 8)
The optimal solution consists in declining Order 2 and 3 and the gain
is 10+8 = 18.
Note that the solution made of Order 1 and 3 is feasible (the airplane is rented with no interruption from time 0 to time 14) but non-optimal.
The first line of the input contains a number T ≤ 30 that indicates the number of test cases to follow. The first line of each test case contains the number of orders n (n ≤ 10000). In the following n lines the orders are given. Each order is described by 3 integer values: The start time of the order st (0 ≤ st < 1000000), the duration d of the order (0 < d < 1000000), and the price p (0 < p < 100000) the customer is ready to pay for this order.
You are required to compute an optimal solution. For each test case your program has to write the total price paid by the airlines.
Input: 1 4 0 5 10 3 7 14 5 9 7 6 9 8 Output: 18Warning: large Input/Output data, be careful with certain languages
Thanks @csals I did the same mistake.
Nice problem.. AC in one goLast edit: 2020-07-13 14:30:50
The 2nd column is duration not end time. Wasted 1 hr !!
If anyone doesn't get it...read on geeksofgeeks. Really good explanation is given and good understanding of this problem's category gets formed.
please don't refer spoj toolkit , it has wrong answers.
Nice One!!!Dp+Binary Search :)....The problem statement is wrong...end time and starting time of different jobs cant be same....for Top-Down approach,precalculate next index to choose using Binary Search!!
Can any one tell what's wrong with this approach --> Sorting by start time and each time making two choices of either selecting(if its start time is greater than the end time of last chosen job) or not selecting the current job and then returning the max of both the answers ..Last edit: 2018-05-17 14:08:48
for people refering spoj toolkit it seems they have given wrong input-output . costed me 2 WA
job scheduling .... with linear search and cin/cout - 0.18