RPLH - Hard Launching
Felix, the cat, decided to play in the afternoon with some melons, he built a “melon launcher” and started pointing to targets. Soon he noticed that the melons sometimes overflies the victims or don't even get close to them.
The melon launcher can be rotated so it can shoot from an angle from 0 to 45 degrees.
Felix isn't good at maths, so he ask you to code a program that, given the target (in meters) distance and the speed (in meters / sec) you can give him the perfect angle for the melon launcher.
The gravity to be considered is of 9.806 meters / sec^2
PI value to be considered is 2*acos(0.0).
The first line of input will contain an integer T denoting the T test cases, then, T cases will follow. Each of the following line will contain two integer numbers Ta and Sp, denoting the distance of the target and the speed of the melon respectively.
Output the string “Scenario #i: “ where i is the test case you are analyzing followed by a single number D, denoting the Degrees necessary to do the launch, if the launching can't be done, output D as -1. the number must have a precision of 2 decimal digits.
Input: 3 10 10 10 9 8 9 Output: Scenario #1: 39.35 Scenario #2: -1 Scenario #3: 37.79
0 < Ta, Sp < 10000
Alert during conversion..
for inverse, use acos(x) or asin(x) in c :-)
do this with physics...
- brag at every solved problem comments about how "EZ" it was,
here the given distance is the horizontal range of projectile.
Submitted in C - AC - time=0.00
so we physics now :)
remember there is a space betweeen colon and answer /.......costed me 2 wa before enlightment
2 TLE plzzzz helppp