TOURIST - Tourist
A lazy tourist wants to visit as many interesting locations in a city as possible without going one
step further than necessary. Starting from his hotel, located in the north-west corner of city, he
intends to take a walk to the south-east corner of the city and then walk back. When walking to
the south-east corner, he will only walk east or south, and when walking back to the north-west
corner, he will only walk north or west. After studying the city map he realizes that the task is not
so simple because some areas are blocked. Therefore he has kindly asked you to write a program
to solve his problem.
Given the city map (a 2D grid) where the interesting locations and blocked areas are marked, determine the maximum number of interesting locations he can visit. Locations visited twice are only counted once.
The first line in the input contains the number of test cases (at most 20). Then follow the cases.
Each case starts with a line containing two integers, W and H (2 ≤ W , H ≤ 100), the width and
the height of the city map. Then follow H lines, each containing a string with W characters with
the following meaning:
. Walkable area
* Interesting location (also walkable area)
# Blocked area
You may assume that the upper-left corner (start and end point) and lower-right corner (turning point) are walkable, and that a walkable path of length H + W − 2 exists between them.
For each test case, output a line containing a single integer: the maximum number of interesting locations the lazy tourist can visit.
Input: 2 9 7 *........ .....**#. ..**...#* ..####*#. .*.#*.*#. ...#**... *........ 5 5 .*.*. *###. *.*.* .###* .*.*. Output: 7 8
A very interesting problem, kudos to the setter.
use dp[x1][y1][x2] and dp==-1 => unmarked, dp==-INF => blocked
very good question:)
Nice problem.Learnt something new.
Can anyone explain how the answer to following test case could be 4????
Very interesting problem,huge upgrade on the problem in which you just have to go from the top-left to the bottom-right corner.
Solving this problem was totally worth it! :D
Accepted after trying a whole day!
The following test case is mentioned in an earlier comment. Why is it said to be an invalid test case