VHELSING  Van Helsings gun
In Transylvania, 1753, Dracula has returned from his long sleep, now, of course, someone needs to face it or humanity will be utterly destroyed by the evil bloodthirsty Dracula.
The only one with enough courage to face Dracula is Van Helsing. The only weapon that can defeat him is the silver gun, but Van Helsing does not know the exact amount of powder required for a deadly shot.
The magazine of gunpowder has the form given by intersection of three cylinders of radius r and infinite height, mutually orthogonal, and centered on the axes $X$, $Y$ and $Z$ in $R^3$, as shown below. Your task is to help Van Helsing calculate the exact amount of gunpowder that he will need, ie, the volume of the powder magazine.
Input
The first line of input contains an integer 1 ≤ T ≤ 100 representing the number of test cases. For each of the following
lines contain an integer 0 ≤ R ≤ 100, as shown above.
Output
For each case print one line containing the amount of gunpowder that Van Helsing needs, with 4 decimal places.
Example
Input: 2
0
1 Output: 0.0000
4.6863
hide comments
farhan764:
20160203 20:28:12
submit it in python very easy......only one math formula to finding volume of this intersection 

shubham:
20150819 22:45:18
use double instead of float. 

ROHIT Kumar:
20150726 13:10:10
read this for solving it


Dushyant Singh:
20150601 16:33:33
Just used direct formula. Don't know how to derive it. :/ 

HITESH GARG:
20141220 22:25:57
Steinmetz solid ;) 

jinkies:
20141014 15:01:05
pretty easy 

Samar Holkar:
20140623 14:39:28
why gives wrong answer with floats???? 

`Ak:
20140607 11:16:27
Tricylinder easy one AC! in first go :) :) 

shantanu:
20140518 17:03:17
okay, so i'm getting every answer correct. still NZEC here. 

Shanks:
20131202 18:33:40
easy math..for the precesion problem 0.4lf

Added by:  Paulo Costa 
Date:  20120116 
Time limit:  1s 
Source limit:  50000B 
Memory limit:  1536MB 
Cluster:  Cube (Intel G860) 
Languages:  All except: ASM64 
Resource:  IME/USP 2  Brazilian ICPC Training Camp, JanFeb/2012 